使用凌空庫通過PHP文件的JSON對象

Question

你好，我是用凌空庫從一個MySQL database.But無法解析JSON object.This獲取數據是我的主要ativity的代碼

public class MainActivity extends Activity { 
    private static final String TAG = MainActivity.class.getSimpleName(); 
    private ListView listView; 
    private FeedListAdapter listAdapter; 
    private List<FeedItem> feedItems; 
    private String URL_FEED = "http://someurl/feed.json"; 

    @SuppressLint("NewApi") 
    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     listView = (ListView) findViewById(R.id.list); 

     feedItems = new ArrayList<FeedItem>(); 

     listAdapter = new FeedListAdapter(this, feedItems); 
     listView.setAdapter(listAdapter); 

     // These two lines not needed, 
     // just to get the look of facebook (changing background color & hiding the icon) 
     getActionBar().setBackgroundDrawable(new ColorDrawable(Color.parseColor("#3b5998"))); 
     getActionBar().setIcon(
       new ColorDrawable(getResources().getColor(android.R.color.transparent))); 

     // We first check for cached request 
     Cache cache = AppController.getInstance().getRequestQueue().getCache(); 
     Entry entry = cache.get(URL_FEED); 



     if (entry != null) { 
     //fetch the data from cache 
      try { 
       String data = new String(entry.data, "UTF-8"); 
      try { 
       parseJsonFeed(new JSONObject(data)); 
      } catch (JSONException e) { 
       e.printStackTrace(); 
      } 
     } catch (UnsupportedEncodingException e) { 
      e.printStackTrace(); 
     } 

      } else { 
     //making fresh volley request and getting json 
      JsonObjectRequest jsonReq = new JsonObjectRequest(Method.GET, 
       URL_FEED, null, new Response.Listener<JSONObject>() { 

      @Override 
      public void onResponse(JSONObject response) { 
       VolleyLog.d(TAG, "Response: " + response.toString()); 
      if (response != null) { 
        parseJsonFeed(response); 
       } 
      } 
      }, new Response.ErrorListener() { 

      @Override 
      public void onErrorResponse(VolleyError error) { 
       VolleyLog.d(TAG, "Error: " + error.getMessage()); 
      } 
      }); 

     //Adding request to volley request queue 
      AppController.getInstance().addToRequestQueue(jsonReq); 
     } 

     } 

     /** 
     * Parsing json reponse and passing the data to feed view list adapter 
     * */ 
    private void parseJsonFeed(JSONObject response) { 
     try { 
      JSONArray feedArray = response.getJSONArray("feed"); 

      for (int i = 0; i < feedArray.length(); i++) { 
       JSONObject feedObj = (JSONObject) feedArray.get(i); 

       FeedItem item = new FeedItem(); 
       item.setId(feedObj.getInt("id")); 
       item.setName(feedObj.getString("name")); 

       // Image might be null sometimes 
       String image = feedObj.isNull("image") ? null : feedObj 
         .getString("image"); 
       item.setImge(image); 
       item.setStatus(feedObj.getString("status")); 
       item.setProfilePic(feedObj.getString("profilePic")); 
       item.setTimeStamp(feedObj.getString("timeStamp")); 

       // url might be null sometimes 
       String feedUrl = feedObj.isNull("url") ? null : feedObj 
         .getString("url"); 
       item.setUrl(feedUrl); 

       feedItems.add(item); 
      } 

      // notify data changes to list adapater 
      listAdapter.notifyDataSetChanged(); 
     } catch (JSONException e) { 
      e.printStackTrace(); 
     } 
    } 





    @Override 
    public boolean onCreateOptionsMenu(Menu menu) { 
     getMenuInflater().inflate(R.menu.menu_main, menu); 
     return true; 
    } 

在上面的代碼傳遞的URL是一個JSON對象和JSON對象的像

{ 
    "feed": [ 
     { 
      "id": 1, 
      "name": "National Geographic Channel", 
      "image": "http://api.androidhive.info/feed/img/cosmos.jpg", 
      "status": "\"Science is a beautiful and emotional human endeavor,\" says Brannon Braga, executive producer and director. \"And Cosmos is all about making science an experience.\"", 
      "profilePic": "http://api.androidhive.info/feed/img/nat.jpg", 
      "timeStamp": "1403375851930", 
      "url": null 
     }, 
     { 
      "id": 2, 
      "name": "TIME", 
      "image": "http://api.androidhive.info/feed/img/time_best.jpg", 
      "status": "30 years of Cirque du Soleil's best photos", 
      "profilePic": "http://api.androidhive.info/feed/img/time.png", 
      "timeStamp": "1403375851930", 
      "url": "http://ti.me/1qW8MLB" 
     } 
] 
} 

結構，但我想傳遞一個PHP文件而不是在URL_FEED variable.The PHP文件中使用的JSON對象的其我正在使用的是

<?php 
define('HOST','mysql.******.in'); 
define('USER','someuser'); 
define('PASS','*****'); 
define('DB','somedb'); 

$con = mysqli_connect(HOST,USER,PASS,DB); 

$sql = "select * from timeline"; 

$res = mysqli_query($con,$sql); 

$result = array(); 

while($row = mysqli_fetch_array($res)){ 
array_push($result, 
array('id'=>intval($row[0]), 
'name'=>$row[1], 
'image'=>$row[2], 
'status'=>$row[3], 
'profilePic'=>$row[4], 
'timestamp'=>$row[5], 
'url'=>$row[6] 
)); 
} 

header('Content-type: application/json'); 
echo json_encode(array("feed"=>$result),JSON_PRETTY_PRINT); 

mysqli_close($con); 

?> 

和我的PHP文件的輸出是

{ 
    "feed": [ 
     { 
      "id": 1, 
      "name": "helpme", 
      "image": "http:\/\/api.androidhive.info\/feed\/img\/cosmos.jpg", 
      "status": "Hello everyone", 
      "profilePic": "http:\/\/api.androidhive.info\/feed\/img\/nat.jpg", 
      "timestamp": "2015-08-21 19:11:15", 
      "url": "http:\/\/ti.me\/1qW8MLB" 
     } 
    ] 
} 

這裏的URL格式被幹擾，將在解析該文件影響。 即使我使用的php文件輸出是一個json對象，但傳遞它的鏈接不工作。我的意思是在所使用的列表視圖中沒有任何顯示。 任何人都可以請幫助我知道如果我使用的PHP文件是正確的，如果不是如何可以糾正。我們可以在URL_FEED變量而不是json對象中使用php文件。 預先感謝您。

Answer 1

所有你所要做的就是使用JSON_UNESCAPED_SLASHES

您的迴音行更改爲：

echo json_encode(array("feed"=>$result), JSON_UNESCAPED_SLASHES | JSON_PRETTY_PRINT);