我有一個問題,與排雷庫得到json。 這是我的JSON:得到具有整數與排球庫json
{"result":1}
的PHP的MySQL數據庫和顯示結果在這個JSON文件的代碼行數。 計數的數量是整數。
,這是我的代碼得到這個JSON:
private void getData() {
//url + id of row that want to count
String url = Config.DATA_URL_COUNT +"1";
StringRequest stringRequest = new StringRequest(url, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
//loading.setVisibility(View.INVISIBLE);
showJSON(response);
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
// Toast.makeText(this,error.getMessage().toString(), Toast.LENGTH_LONG).show();
}
});
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);
}
private void showJSON(String response) {
int name = 0;
try {
JSONObject jsonObject = new JSONObject(response);
JSONArray result = jsonObject.getJSONArray(Config.TAG_RESULT);
JSONObject collegeData = result.getJSONObject(0);
name = jsonObject.getInt(Config.JSON_ARRAY);
} catch (JSONException e) {
e.printStackTrace();
}
String count = String.valueOf(name);
rowcount_kargozarybime.setText(count); //insert result in textview
}
,這是我的PHP代碼:
<?php
if($_SERVER['REQUEST_METHOD']=='GET'){
$categoryid = $_GET['categoryid'];
define('HOST','144.76.10.250');
define('USER','cp21983_test');
define('PASS','*******');
define('DB','cp21983_marivanjobs');
$con = mysqli_connect(HOST,USER,PASS,DB);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
mysqli_query($con,"SET character_set_results=utf8,character_set_client=utf8,character_set_connection=utf8, character_set_database=utf8,character_set_server=utf8");
$sql="SELECT * FROM jobs WHERE categoryid='".$categoryid."'";
if ($result=mysqli_query($con,$sql))
{
// Return the number of rows in result set
$rowcount=mysqli_num_rows($result);
echo json_encode(array("result"=>$rowcount));
// Free result set
mysqli_free_result($result);
}
mysqli_close($con);
}
我也應該心存感激,如果有人能幫助我。
而你的問題是什麼? – f1sh
@ f1sh在文本視圖中不顯示結果 –
您可以添加響應結果格式嗎? –