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我正在將我的語法重組爲兩個文件以容納樹語法; Lua.g和LuaGrammar.g。 Lua.g將擁有我所有的詞法分析器規則，而LuaGrammar.g將具有我所有的樹語法和分析器規則。然而，當我嘗試編譯LuaGrammar.g我得到以下錯誤：嘗試將語法重組爲兩個文件時出現異常ANTLR錯誤
[00:28:37] error(10): internal error: C:\Users\RCIX\Desktop\AguaLua\Project\trunk\AguaLua\AguaLua\ANTLR Data\LuaGrammar.g : java.lang.IllegalArgumentException: Can't find template ruleRefBang.st; group hierarchy is [CSharp2]
org.antlr.stringtemplate.StringTemplateGroup.lookupTemplate(StringTemplateGroup.java:507)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:392)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:404)
org.antlr.stringtemplate.StringTemplateGroup.lookupTemplate(StringTemplateGroup.java:484)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:392)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:404)
org.antlr.stringtemplate.StringTemplateGroup.lookupTemplate(StringTemplateGroup.java:484)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:392)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:404)
org.antlr.grammar.v2.CodeGenTreeWalker.getRuleElementST(CodeGenTreeWalker.java:152)
org.antlr.grammar.v2.CodeGenTreeWalker.atom(CodeGenTreeWalker.java:1986)
org.antlr.grammar.v2.CodeGenTreeWalker.element(CodeGenTreeWalker.java:1708)
org.antlr.grammar.v2.CodeGenTreeWalker.element(CodeGenTreeWalker.java:1556)
org.antlr.grammar.v2.CodeGenTreeWalker.alternative(CodeGenTreeWalker.java:1306)
org.antlr.grammar.v2.CodeGenTreeWalker.block(CodeGenTreeWalker.java:1081)
org.antlr.grammar.v2.CodeGenTreeWalker.ebnf(CodeGenTreeWalker.java:1871)
org.antlr.grammar.v2.CodeGenTreeWalker.element(CodeGenTreeWalker.java:1704)
org.antlr.grammar.v2.CodeGenTreeWalker.alternative(CodeGenTreeWalker.java:1306)
org.antlr.grammar.v2.CodeGenTreeWalker.block(CodeGenTreeWalker.java:1081)
org.antlr.grammar.v2.CodeGenTreeWalker.rule(CodeGenTreeWalker.java:797)
org.antlr.grammar.v2.CodeGenTreeWalker.rules(CodeGenTreeWalker.java:588)
org.antlr.grammar.v2.CodeGenTreeWalker.grammarSpec(CodeGenTreeWalker.java:530)
org.antlr.grammar.v2.CodeGenTreeWalker.grammar(CodeGenTreeWalker.java:336)
org.antlr.codegen.CodeGenerator.genRecognizer(CodeGenerator.java:432)
org.antlr.Tool.generateRecognizer(Tool.java:641)
org.antlr.Tool.process(Tool.java:454)
org.antlr.works.generate.CodeGenerate.generate(CodeGenerate.java:104)
org.antlr.works.generate.CodeGenerate.run(CodeGenerate.java:185)
java.lang.Thread.run(Unknown Source)
而且，我發現了以下錯誤：
[00:34:58] error(100): C:\Users\RCIX\Desktop\AguaLua\Project\trunk\AguaLua\AguaLua\ANTLR Data\Lua.g:0:0: syntax error: codegen: <AST>:0:0: unexpected end of subtree
試圖產生Lua.g.時爲什麼我會收到這些錯誤，我該如何解決這些錯誤？ （使用ANTLR V3，能夠提供語法文件）
更新：這裏是我正在編譯的語法文件。
tree grammar LuaGrammar;
options {
backtrack=true;
language=CSharp2;
output=AST;
tokenVocab=Lua;
filter=true;
ASTLabelType=CommonTree;
}
assignment
:
^('=' left=NAME right=NAME) {Ast. };
/*
chunk : (stat (';'!)?)* (laststat (';'!)?)?;
block : chunk;
stat : varlist1 '='^ explist1 |
functioncall |
doblock |
'while'^ exp doblock |
'repeat'^ block untilrule |
'if'^ exp thenchunk elseifchunk* elsechunk? 'end'! |
'for'^ forinitializer doblock |
'for'^ namelist inlist doblock |
'function'^ funcname funcbody |
'local' 'function' NAME funcbody |
'local'^ namelist localstat? ;
localstat
: '='^ explist1;
untilrule
: 'until'^ exp;
elseifchunk
: 'elseif'^ exp thenchunk;
thenchunk
: 'then'^ block;
elsechunk
: 'else'^ block;
forinitializer
: NAME '='^ exp ','! exp (','! exp)?;
doblock
: 'do'^ block 'end'!;
inlist
: 'in'^ explist1;
laststat : 'return'^ (explist1)? | 'break';
dotname : '.'! funcname;
colonname
: ':' NAME;
funcname : NAME^ (dotname | colonname)?;
varlist1 : var (','! var)*;
namelist : NAME (','! NAME)*;
explist1 : (exp ','!)* exp;
*/
/*
exp : expelement (binop^ exp)* ;
expelement
: ('nil' | 'false' | 'true' | number | stringrule | '...' | /*function |*\ prefixexp | tableconstructor | unop exp);
var: (namevar | dotvar | expvar | arrayvar)?;
namevar
: NAME^ var;
dotvar
: '.'! var;
expvar
: '('^ exp ')'! var;
arrayvar
: '['^ var ']'! var;
varSuffix: nameAndArgs* ('[' exp ']' | '.' NAME);
prefixexp: varOrExp nameAndArgs*;
functioncall: varOrExp nameAndArgs+;
varOrExp: var | '('! exp ')'!;
nameAndArgs: (':' NAME)? argsrule;
argsrule : '(' (explist1)? ')' | tableconstructor | stringrule ;
function : 'function' funcbody;
funcbody : funcparams funcblock;
funcblock
: ')'^ block 'end'!;
funcparams
: '('^ parlist1? ;
parlist1 : namelist (','! '...')? | '...';
tableconstructor : '{'^ (fieldlist)? '}'!;
fieldlist : field (fieldsep! field)* (fieldsep!)?;
field : '['! exp ']'! '='^ exp | NAME '='^ exp | exp;
*/
fieldsep : ',' | ';';
binop : '+' | '-' | '*' | '/' | '^' | '%' | '..' |
'<' | '<=' | '>' | '>=' | '==' | '~=' |
'and' | 'or';
unop : '-' | 'not' | '#';
number : INT | FLOAT | EXP | HEX;
stringrule : NORMALSTRING | CHARSTRING | LONGSTRING;
Lua.g：
/*
* Lua 5.1 grammar
*
* Nicolai Mainiero
* May 2007
*
* This is a Lua (http://www.lua.org) grammar for the version 5.1 for ANTLR 3.
* I tested it with basic and extended examples and it worked fine. It is also used
* for LunarEclipse (http://lunareclipse.sf.net) a Lua editor based on Eclipse.
*
* Thanks to Johannes Luber and Gavin Lambert who helped me with some mutually left recursion.
*
*/
grammar Lua;
options {
backtrack=true;
language=CSharp2;
//output=AST;
//ASTLabelType=CommonTree;
}
@lexer::namespace{AguaLua}
chunk : (stat (';'!)?)* (laststat (';'!)?)?;
block : chunk;
stat : varlist1 '='^ explist1 |
functioncall |
doblock |
'while'^ exp doblock |
'repeat'^ block untilrule |
'if'^ exp thenchunk elseifchunk* elsechunk? 'end'! |
'for'^ forinitializer doblock |
'for'^ namelist inlist doblock |
'function'^ funcname funcbody |
'local' 'function' NAME funcbody |
'local'^ namelist localstat? ;
localstat
: '='^ explist1;
untilrule
: 'until'^ exp;
elseifchunk
: 'elseif'^ exp thenchunk;
thenchunk
: 'then'^ block;
elsechunk
: 'else'^ block;
forinitializer
: NAME '='^ exp ','! exp (','! exp)?;
doblock
: 'do'^ block 'end'!;
inlist
: 'in'^ explist1;
laststat : 'return'^ (explist1)? | 'break';
dotname : '.'! funcname;
colonname
: ':' NAME;
funcname : NAME^ (dotname | colonname)?;
varlist1 : var (','! var)*;
namelist : NAME (','! NAME)*;
explist1 : (exp ','!)* exp;
exp : expelement (binop^ exp)* ;
expelement
: ('nil' | 'false' | 'true' | number | stringrule | '...' | function | prefixexp | tableconstructor | unop exp);
var: (namevar | dotvar | expvar | arrayvar)?;
namevar
: NAME^ var;
dotvar
: '.'! var;
expvar
: '('^ exp ')'! var;
arrayvar
: '['^ var ']'! var;
varSuffix: nameAndArgs* ('[' exp ']' | '.' NAME);
prefixexp: varOrExp nameAndArgs*;
functioncall: varOrExp nameAndArgs+;
varOrExp: var | '('! exp ')'!;
nameAndArgs: (':' NAME)? argsrule;
argsrule : '(' (explist1)? ')' | tableconstructor | stringrule ;
function : 'function' funcbody;
funcbody : funcparams funcblock;
funcblock
: ')'^ block 'end'!;
funcparams
: '('^ parlist1? ;
parlist1 : namelist (','! '...')? | '...';
tableconstructor : '{'^ (fieldlist)? '}'!;
fieldlist : field (fieldsep! field)* (fieldsep!)?;
field : '['! exp ']'! '='^ exp | NAME '='^ exp | exp;
fieldsep : ',' | ';';
binop : '+' | '-' | '*' | '/' | '^' | '%' | '..' |
'<' | '<=' | '>' | '>=' | '==' | '~=' |
'and' | 'or';
unop : '-' | 'not' | '#';
number : INT | FLOAT | EXP | HEX;
stringrule : NORMALSTRING | CHARSTRING | LONGSTRING;
// LEXER
NAME :('a'..'z'|'A'..'Z'|'_')(options{greedy=true;}: 'a'..'z'|'A'..'Z'|'_'|'0'..'9')*
;
INT : ('0'..'9')+;
FLOAT :INT '.' INT ;
EXP : (INT| FLOAT) ('E'|'e') ('-')? INT;
HEX :'0x' ('0'..'9'| 'a'..'f')+ ;
NORMALSTRING
: '"' (EscapeSequence | ~('\\'|'"'))* '"'
;
CHARSTRING
: '\'' (EscapeSequence | ~('\''|'\\'))* '\''
;
LONGSTRING
: '['('=')*'[' (EscapeSequence | ~('\\'|']'))* ']'('=')*']'
;
fragment
EscapeSequence
: '\\' ('b'|'t'|'n'|'f'|'r'|'\"'|'\''|'\\')
| UnicodeEscape
| OctalEscape
;
fragment
OctalEscape
: '\\' ('0'..'3') ('0'..'7') ('0'..'7')
| '\\' ('0'..'7') ('0'..'7')
| '\\' ('0'..'7')
;
fragment
UnicodeEscape
: '\\' 'u' HexDigit HexDigit HexDigit HexDigit
;
fragment
HexDigit : ('0'..'9'|'a'..'f'|'A'..'F') ;
COMMENT
: '--[[' (options {greedy=false;} : .)* ']]' {Skip();}
;
LINE_COMMENT : '--' (~ NEWLINE)* {Skip();};
fragment NEWLINE : '\r'|'\n' | '\r\n' ;
WS : (' '|'\t'|'\u000C') {Skip();};
（兩者都基於在ANTLR的網站，Lua的5.1語法由尼古拉Mainero和可用的生產的語法） 如果我不是這個取消註釋了，說到與上面的錯誤。
隨着「編譯LuaGrammar.g」我假設你的意思是生成一個解析器和詞法分析器？什麼時候出現關於'ruleRefBang.st'的錯誤？它是否顯示在您發佈的語法上（包含所有評論）？如果不是的話，可否請你發佈拋出這個關於'ruleRefBang.st'錯誤的語法？ –
如果您取消註釋提供的語法中的部分並嘗試生成代碼（在同一個目錄中使用Lua.g，我將編輯該文件），它會拋出錯誤。但是，它的評論是這樣的，它會生成很好的結果。詞法分析器部分也生成很好，我在那裏沒有問題。 – RCIX