真的是新來的symfony,來自yii。如何在symfony中插入與ManyToOne關係的user_id?
我無法將user_id插入到具有ManyToOne關係的另一個表中。 當我說我想插入的id表的實體,我用: $en->setUser($user_id);
的結果是: SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'user_id' cannot be null
但是當我做var_dump($user_id);
有一個ID。 那麼如何插入user_id與多對一的關係?
[更新] TableUser實體
<?php
namespace User\Bundle\RegisterBundle\Entity;
use Symfony\Component\Validator\Constraints as Assert;
use Doctrine\ORM\Mapping as ORM;
/**
* User
*
* @ORM\Table(name="user", indexes={@ORM\Index(name="user_id", columns={"user_id"})})
* @ORM\Entity
*/
class User
{
/**
* @var integer
*
* @ORM\Column(name="user_id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="IDENTITY")
*/
private $userId;
public function getUserId()
{
return $this->userId;
}
}
?>
TableSomeModel實體具有與USER_ID
<?php
namespace \Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* SomeModel
*
* @ORM\Table(name="SomeModel", indexes={@ORM\Index(name="user_id", columns={"user_id"})})
* @ORM\Entity
*/
class SomeModel
{
/**
* @var \User
*
* @ORM\ManyToOne(targetEntity="User")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="user_id", referencedColumnName="user_id")
* })
*/
private $user;
/**
* Set user
*
* @param \Entity\User $user
* @return App
*/
public function setUser(\Entity\User $user)
{
return $this->user;
}
/**
* Get user
*
* @return \Entity\User
*/
public function getUser()
{
return $this->user;
}
}
多對一關係在控制器
$en = new SomeModel();
var_dump($user_id); //not null
$en->setUser($user_id); //always null;
顯示兩個相關實體請 –
能否請你分享其中聲明該關係的代碼(YML文件或註解? – Praveesh