連接兩個不同的MySQL結果查詢通過追加新的列

我似乎無法找到一種方法如何組合/加入的，因爲我在何處及以要求兩個簡單的SQL結果的查詢。連接兩個不同的MySQL結果查詢通過追加新的列

簡單地說，我想這個查詢的結果是：

SELECT Nationality, MAX(ActorName) as Oldest, 
FROM ACTOR 
WHERE BirthDate IN 
(SELECT MIN(BirthDate) as MinBday FROM ACTOR GROUP BY Nationality) 
GROUP BY Nationality

導致此：

SELECT Nationality, MAX(ActorName) as Oldest, 
FROM ACTOR 
WHERE BirthDate IN 
(SELECT MAX(BirthDate) as MinBday FROM ACTOR GROUP BY Nationality) 
GROUP BY Nationality

：

+------------+--------------+ 
| nationality| oldest  | 
+------------+--------------+ 
| american | brad pitt | 
+------------+--------------+ 
| british | pierce bro | 
+------------+--------------+ 
| italian | monica bellu | 
+------------+--------------+

與此查詢的結果可以加入這會導致這樣的：

+------------+--------------+ 
| nationality| youngest  | 
+------------+--------------+ 
| american | angelina j | 
+------------+--------------+ 
| british | jason stat | 
+------------+--------------+ 
| italian | paul gia  | 
+------------+--------------+

，以便具有所得表如下：

+------------+--------------+--------------+ 
|nationality | oldest  | youngest  | 
+------------+--------------+--------------+ 
| american | brad pitt | angelina j | 
+------------+--------------+--------------+ 
| british | pierce bro | jason stat | 
+------------+--------------+--------------+ 
| italian | monica bellu | paul gia  | 
+------------+--------------+--------------+

注：2個查詢之間的唯一區別是MIN（出生日期），用於最古老的出生日期，和MAX（出生日期），用於最小的生日。

來源

2016-12-07 jmigdelacruz

一個非常醜陋的SQL可以跟隨，不是最有效的，只是一個方法。

SELECT 
    t1.Nationality, t1.Oldest, t2.youngest 
FROM (
    SELECT Nationality, MAX(ActorName) as Oldest -- , 
    FROM ACTOR 
    WHERE BirthDate IN 
    (SELECT MIN(BirthDate) as MinBday FROM ACTOR GROUP BY Nationality) 
    GROUP BY Nationality 
) t1 
JOIN (
    SELECT Nationality, MAX(ActorName) as youngest 
    FROM ACTOR 
    WHERE BirthDate IN 
    (SELECT MAX(BirthDate) as MaxBday FROM ACTOR GROUP BY Nationality) 
    GROUP BY Nationality 
) t2 ON t1.Nationality = t2.Nationality

或嘗試此（未測試）：

SELECT 
    Nationality, 
    MAX(CASE WHEN BirthDate = t1.MinBday THEN ActorName ELSE NULL END) as Oldest, 
    MAX(CASE WHEN BirthDate = t1.MaxBday THEN ActorName ELSE NULL END) as youngest 
FROM ACTOR 
JOIN (
    SELECT Nationality, MIN(BirthDate) as MinBday, MAX(BirthDate) as MaxBday 
    FROM ACTOR GROUP BY Nationality) t 
ON ACTOR.Nationality = t.Nationality 
GROUP BY Nationality

來源

2016-12-07 10:23:24 Blank

希望的是直接的（即使醜陋）答案像這樣的工作，但我忘了我在微軟Access這樣做的，有人原因查詢這樣總是結了：'語法錯誤在FROM clause' – jmigdelacruz

@jmigdelacruz更新我的回答，只是多了一個逗號之前'from'。 – Blank

謝謝@forward！第一個查詢效果很好。只是改變了，'加入'到'左連接'，並從'最舊 - '中刪除' - ，' – jmigdelacruz

你可以得到的生日，可與直接加入像

SELECT a.Nationality, MAX(a.ActorName) as Oldest, 
FROM ACTOR a 
JOIN (SELECT Nationality, 
MIN(BirthDate) as MinBday, 
MAX(BirthDate) as MaxBday 
    FROM ACTOR 
    GROUP BY Nationality) xxx 
ON a.Nationality = xxx.Nationality 
AND (a.BirthDate = xxx.MinBday OR a.BirthDate = xxx.MaxBday) 
GROUP BY Nationality;

來源

2016-12-07 10:19:29 Rahul

連接兩個不同的MySQL結果查詢通過追加新的列

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