4
我需要將任意嵌套的Map轉換爲TreeMap。例子:將地圖深層轉換爲TreeMap
Map[Int, String] -> TreeMap[Int, String]
Map[Int, Map[Int, String]] -> TreeMap[Int, TreeMap[Int, String]]
... etc
我有工作與類型體操和隱式轉換解決方案,但是我有一個類型的
trait ToTreeMap[M[_, _], K, V] {
type Result
def treeMap(x: M[K, V]): TreeMap[K, Result]
}
trait LowerPriorityToTreeMap {
implicit def plainMap[K, V](implicit ord: Ordering[K]): ToTreeMap[Map, K, V] =
new ToTreeMap[Map, K, V] {
type Result = V
def treeMap(x: Map[K, V]): TreeMap[K, Result] = TreeMap(x.toArray: _*)
}
}
object ToTreeMap extends LowerPriorityToTreeMap {
implicit def nestedMap[K1, K2, V](implicit inner: ToTreeMap[Map, K2, V], ord: Ordering[K1]): ToTreeMap[Map, K1, Map[K2, V]] = {
new ToTreeMap[Map, K1, Map[K2, V]] {
type Result = TreeMap[K2, inner.Result]
def treeMap(x: Map[K1, Map[K2, V]]): TreeMap[K1, Result] = TreeMap(x.mapValues(v => inner.treeMap(v)).toArray: _*)
}
}
implicit class MapOps[K, V](map: Map[K, V]) {
def asTreeMap(implicit as: ToTreeMap[Map, K, V]) = as.treeMap(map)
}
}
能正常工作的問題,但鍵入ToTreeMap [..]#結果沒有按」 t匹配我需要的TreeMap
import ToTreeMap._
val map: Map[Int, Map[Int, Map[Int, String]]] =
Map(
1000 -> Map(
100 -> Map(
10 -> "aa",
1 -> "bb"
),
99 -> Map(
10 -> "aa",
1 -> "bb"
)
),
999 -> Map(
100 -> Map(
10 -> "aa",
1 -> "bb"
),
99 -> Map(
10 -> "aa",
1 -> "bb"
)
)
)
val m = Map(1 -> "aaa")
println(map.asTreeMap)
println(m.asTreeMap)
// This line fails to compile
val tm: TreeMap[Int, TreeMap[Int, TreeMap[Int, String]]] = map.asTreeMap
任何想法如何正確地做到這一點?
Scalac挑選正確的類型在這個例子:Two dimensional array as a function這是沒有太多不同,這一次,因爲我覺得
我可以解決這個問題的類型與「asIntanceOf」,但我想這樣做沒有這個骯髒黑客攻擊。