PHP - 爲關聯數組添加新的「鍵值」

Question

我正在嘗試幾乎所有將新鍵和其值添加到結果查詢。

$consulta = "SELECT p.id_empleado,count(p.id_empleado) as pendientes,e.nombre,e.apellidos FROM partidas_empleados p "; 
    $consulta.= "inner join empleados e on p.id_empleado=e.id_empleado "; 
    $consulta.= "WHERE abierta=TRUE group by id_empleado"; 

    $sql = $con->prepare($consulta); 
    $ok = $sql->execute(); 
    $query = $sql->fetchAll(PDO::FETCH_ASSOC); 

    for($i=0;$i<count($query);$i++){ 
     //echo "hola"; 
     $fila = $query[$i]; 
     $consulta = "SELECT id_partida FROM partidas_empleados where id_empleado=? "; 
     $sql = $con->prepare($consulta); 
     $ok = $sql->execute(array($fila['id_empleado'])); 
     $sub_query = $sql->fetchAll(PDO::FETCH_ASSOC); 
     //echo $sub_query; 
     //$fila[]= array("lista_partidas"=>$sub_query); 
     $fila['lista_partidas']= $sub_query; 
    } 

$sub_query只是一個asociative陣列

我試圖用lista_partidas添加$sub_query到$query作爲重點的清單。

Answer 1

正如@kunruh和@jeroen所說我正在創建一個副本並修改該副本。

$consulta = "SELECT p.id_empleado,count(p.id_empleado) as pendientes,e.nombre,e.apellidos FROM partidas_empleados p "; 
    $consulta.= "inner join empleados e on p.id_empleado=e.id_empleado "; 
    $consulta.= "WHERE abierta=TRUE group by id_empleado"; 

    $sql = $con->prepare($consulta); 
    $ok = $sql->execute(); 
    $query = $sql->fetchAll(PDO::FETCH_ASSOC); 

    for($i=0;$i<count($query);$i++){ 
     $consulta = "SELECT id_partida FROM partidas_empleados where id_empleado=? "; 
     $sql = $con->prepare($consulta); 
     $ok = $sql->execute(array($fila['id_empleado'])); 
     $sub_query = $sql->fetchAll(PDO::FETCH_ASSOC); 
     $query[$i]['lista_partidas']= $sub_query; 
    }