2012-08-15 54 views
2

我目前有兩個非常複雜的查詢,我使用這些查詢來引入評分。首先是所有的參與者和他們的階段成績,第二個是由每個參與者分組並計算他們的總體排名(階段總和)。mysql加入了兩個非常複雜的查詢

首先查詢以獲得每個階段的所有參與者的得分和排名

SELECT * FROM (
    SELECT alias, catabbr, sh_dq, raw, sdq, dnf, 
@rownum := IF(@stage != stage_name, 1, @rownum + 1) AS rowNum, 
@rank := IF(@prevVal != cTime, @rownum, @rank) AS rank, 
@stage := stage_name as stage_name, 
@prevVal := cTime AS cTime, 
id, zeroTime 
    FROM 
(SELECT @rownum:= 0) rn, 
(SELECT @rank:= 1) av, 
(SELECT @stage:= '') sv, 
(SELECT @prevVal:= 0) pv, 
(SELECT s.stage_name stage_name, sc.alias alias, sc.catAbbr catabbr, sc.sh_dq sh_dq, sc.time raw, sc.id id, sc.sdq sdq, sc.dnf dnf, 
    IF(sc.time = "0", 1, 0) AS zeroTime, 
    ((ROUND(sc.time, 2) + (sc.miss * 5)) + ((sc.proc * 10) + (sc.saf * 10) + (sc.sog * 30)) - (sc.bthPoints)) cTime 
    FROM matches m 
    LEFT JOIN stages s ON s.match_id = m.id 
    LEFT JOIN scores sc ON sc.stage_id = s.id 
    WHERE m.matchuuid = 'E13A4C61-A2B8-48E2-BE1B-1FFB77CC5849' 
    GROUP BY sc.alias, s.stage_name 
    ORDER BY s.stage_name, zeroTime, cTime 
) tv 
) t 
ORDER BY zeroTime, alias, stage_name; 

輸出:

+-----------+---------+-------+-----------------+-----+-----+--------+------+-----------------------+-------+----------+ 
| alias  | catabbr | sh_dq | raw    | sdq | dnf | rowNum | rank | stage_name   | cTime | zeroTime | 
+-----------+---------+-------+-----------------+-----+-----+--------+------+-----------------------+-------+----------+ 
| Back Bob | S  | 0  | 52.9799995422 | 0 | 1 | 54  | 54 | Stage 1    | 92.98 | 0  | 
+-----------+---------+-------+-----------------+-----+-----+--------+------+-----------------------+-------+----------+ 
| Back Bob | S  | 0  | 43.9099998474 | 0 | 0 | 46  | 46 | Stage 2    | 48.91 | 0  | 
+-----------+---------+-------+-----------------+-----+-----+--------+------+-----------------------+-------+----------+ 
| Ben Scal | ES  | 0  | 26.9699993134 | 0 | 0 | 27  | 27 | Stage 1    | 31.97 | 0  | 
+-----------+---------+-------+-----------------+-----+-----+--------+------+-----------------------+-------+----------+ 
| Ben Scal | ES  | 0  | 32.8800010681 | 0 | 0 | 38  | 38 | Stage 2    | 42.88 | 0  | 
+-----------+---------+-------+-----------------+-----+-----+--------+------+-----------------------+-------+----------+ 

二按名稱查詢組參與者,總結他們的隊伍作最後的排名

SELECT alias, catabbr, SUM(cTime) fTime, SUM(rank) fRank, zeroTime, rank 
FROM (
    SELECT alias, catabbr, sh_dq, raw, sdq, dnf, 
@rownum := IF(@stage != stage_name, 1, @rownum + 1) AS rowNum, 
@rank := IF(@prevVal != cTime, @rownum, @rank) AS rank, 
@stage := stage_name as stage_name, 
@prevVal := cTime AS cTime, 
id, zeroTime 
    FROM 
(SELECT @rownum:= 0) rn, 
(SELECT @rank:= 1) av, 
(SELECT @stage:= '') sv, 
(SELECT @prevVal:= 0) pv, 
(SELECT s.stage_name stage_name, sc.alias alias, sc.catAbbr catabbr, sc.sh_dq sh_dq, sc.time raw, sc.id id, sc.sdq sdq, sc.dnf dnf, 
    IF(sc.time = "0", 1, 0) AS zeroTime, 
    ((ROUND(sc.time, 2) + (sc.miss * 5)) + ((sc.proc * 10) + (sc.saf * 10) + (sc.sog * 30)) - (sc.bthPoints)) cTime 
    FROM matches m 
    LEFT JOIN stages s ON s.match_id = m.id 
    LEFT JOIN scores sc ON sc.stage_id = s.id 
    WHERE m.matchuuid = 'E13A4C61-A2B8-48E2-BE1B-1FFB77CC5849' 
    GROUP BY sc.alias, s.stage_name 
    ORDER BY s.stage_name, zeroTime, cTime 
) tv 
) t 
GROUP BY alias 
ORDER BY zeroTime, fRank, fTime; 

輸出:

+-----------+-----------+-----------+-------+-----------+ 
| alias  | catabbr | fTime  | fRank | zeroTime | 
+-----------+-----------+-----------+-------+-----------+ 
| Back Bob | S   | 141.89 | 100 | 0   | 
+-----------+-----------+-----------+-------+-----------+ 
| Ben Scal | ES  | 74.85  | 68 | 0   | 
+-----------+-----------+-----------+-------+-----------+ 

zeroTime列使得我可以按大於0的時間排序,並正確計算排名。

當我嘗試加入他們時,我沒有得到任何結果或任何東西。有沒有辦法將這兩個查詢合併/連接成一個查詢,以便他們輸出以下內容?

+-----------+-----------+-----------+-------+-----------+---------------+---------------+---------------+---------------+ 
| alias  | catabbr | fTime  | fRank | zeroTime | Stage 1 Time | Stage 1 Rank | Stage 2 Time | Stage 2 Rank | 
+-----------+-----------+-----------+-------+-----------+---------------+---------------+---------------+---------------+ 
| Ben Scal | ES  | 74.85  | 68 | 0   | 31.97   | 27   | 42.88   | 38   | 
+-----------+-----------+-----------+-------+-----------+---------------+---------------+---------------+---------------+ 
| Back Bob | S   | 141.89 | 100 | 0   | 92.98   | 54   | 48.91   | 46   | 
+-----------+-----------+-----------+-------+-----------+---------------+---------------+---------------+---------------+ 

這將進入一個PHP頁面,所以我可以遍歷和我需要什麼拉,我試圖做的主要事情是加入這兩個查詢。

我的結構和數據對於sqlfiddle來說太大了。 這裏是比賽和階段結構和插入:http://pastebin.com/YvZevd5j 下面是成績結構和插入:http://pastebin.com/jLBYxMvc

有一點需要注意得是,一場比賽可以有1個或多個階段,1個或多個particpants。

回答

0

這個答案可能無法很好地擴展,因爲您需要知道階段的數量,但也許您可以使用循環或其他應用程序來處理它。這是一個簡化的版本,您可以修改它以處理您的數據。

SELECT 
    alias, 
    catAbbr, 
    sum(fTime) as fTime, 
    sum(fRank) as fRank, 
    sum(zeroTime) as zeroTime, 
    sum(Stage_1_Time) as stage_1_Time, 
    sum(Stage_1_Rank) as Stage_1_Rank, 
    sum(Stage_2_Time) as stage_2_Time, 
    sum(Stage_2_Rank) as Stage_2_Rank 
FROM (
    SELECT 
    alias, 
    catAbbr, 
    0 as fTime, 
    0 as fRank, 
    0 as zeroTime, 
    Stage_1_Time as stage_1_Time, 
    Stage_1_Rank as Stage_1_Rank, 
    0 as stage_2_Time, 
    0 as Stage_2_Rank 
    FROM (query that gets stage 1 info) 
    UNION 
    SELECT 
    alias, 
    catAbbr, 
    0 as fTime, 
    0 as fRank, 
    0 as zeroTime, 
    0 as stage_1_Time, 
    0 as Stage_1_Rank, 
    stage_2_Time as stage_2_Time, 
    Stage_2_Rank as Stage_2_Rank 
    FROM (query that gets stage 2 info) 
    UNION 
    SELECT 
    alias, 
    catAbbr, 
    fTime as fTime, 
    fRank as fRank, 
    zeroTime as zeroTime, 
    0 as stage_1_Time, 
    0 as Stage_1_Rank, 
    0 as stage_2_Time, 
    0 as Stage_2_Rank 
    FROM (query that gets averaged info) 
) temp 
GROUP BY alias, catAbbt 
+0

這將工作,如果我事先知道多少個階段,但我不這樣它必須是動態的。我已經提前找到了一種使用這兩種查詢並通過php合併數據的方法。儘管感謝您的建議。 – codivist 2012-08-16 18:10:02