//Query = c.PurchaseDate == new DateTime(2011, 11, 29) && c.Name
// == "Elizabeth Brown")
IQueryable<Customer> customers = _customers.AsQueryable<Customer>();
//Predicate parameter
ParameterExpression parameter = Expression.Parameter(typeof(Customer),
"customer");
//Create left expression
Expression left = Expression.Property(parameter, typeof(Customer)
.GetProperty("PurchaseDate"));
Expression right = Expression.Constant(new DateTime(2011, 11, 29));
Expression leftExp = Expression.Equal(left, right);
//Create right expression tree
left = Expression.Property(parameter, typeof(Customer).GetProperty("Name"));
right = Expression.Constant("Elizabeth Brown", typeof(string));
Expression rightExp = Expression.Equal(left, right);
//Combine the expressions into expression tree
Expression expressionTree = Expression.AndAlso(leftExp, rightExp);
//Create an expression tree that represents the expression
MethodCallExpression methodCall = Expression.Call(
typeof(Queryable),
"Where",
new Type[] { customers.ElementType },
customers.Expression,
Expression
.Lambda<Func<Customer, bool>>
(expressionTree, new ParameterExpression[] { parameter }));
// Create an executable query from the expression tree.
IQueryable<Customer> results =
customers.Provider.CreateQuery<Customer>(methodCall);
// Enumerate the results
foreach (Customer customer in results)
{
Console.WriteLine("{0} {1}", customer.Name, customer.PurchaseDate);
}
Console.ReadLine();
我完成了這樣的任務。 IQueryable是真的很奇妙的東西。請享用!
哇!這令人印象深刻! 「Expression left = Expression.Property(pe,typeof(Customer)'應該有'parameter'而不是'pe'吧? – gideon 2012-01-17 08:38:37
實際上,在您的現實生活中,您必須重寫一個抽象ExpressionVisitor類來訪問並擠出這些值在運行時,但爲了演示的目的,我在靜態上下文中創建了這三個表達式值 – user1135594 2012-01-17 14:15:02
是的,你是對的我在準備示例時犯了一個錯誤,但現在已經糾正了。爲了說明我創建了lambda子句的左和右表達式,相應的c.PurchaseDate == new DateTime(2011,11,29)&& c.Name ==「Elizabeth Brown」ParameterExpression參數只定義類型和參數c本身。 – user1135594 2012-01-17 21:55:52