在toat消息

Question

創建一個線程我有以下代碼：

String state= bundle.getString(TelephonyManager.EXTRA_STATE); 
if (state.equalsIgnoreCase(TelephonyManager.EXTRA_INCOMING_NUMBER) 
{ 
Toast toast= new Toast(context); 
toast.setGravity(Gravity.TOP,0,0); 
toast.setDuration(Toast.Length_LONG); 
toast.makeText(..).show(); 
toast.show(); 
} 

我需要保持敬酒，直到有人應答的電話。怎麼做？ 我知道我必須創建並開始一個線程，當我有來電號碼，並在該人回答時停止線程。如何做到這一點？

THX

Answer 1

嘗試這樣的..

Toast.Length_LONG gives toast for only 3.5 seconds.. 

所以..創造3.5秒的countdowntimer像this..in您的活動的onCreate

String state= bundle.getString(TelephonyManager.EXTRA_STATE); 
MyCount counter; 
counter=new MyCount(3500,1000); 
counter.start(); 

mycount的類..

public class MyCount extends CountDownTimer{ 
public MyCount(long millisInFuture, long countDownInterval) { 
super(millisInFuture, countDownInterval); 
} 
@Override 
public void onFinish() { 
if (state.equalsIgnoreCase(TelephonyManager.EXTRA_INCOMING_NUMBER){ 
    Toast toast= new Toast(youractivity.this); 
toast.setGravity(Gravity.TOP,0,0); 
toast.setDuration(Toast.Length_LONG); 
toast.makeText(..).show(); 
toast.show(); 
    counter= new MyCount(3500,1000); 
counter.start(); 
    } 

} 
@Override 
public void onTick(long millisUntilFinished) { 
    } 
} 
} 

這不斷顯示烤麪包，直到你接聽電話..或你的來電因超時而結束。