0
請看看這段代碼無法找出實際的錯誤編輯在表中的數據：無法使用PHP形式
這是PHP上傳代碼：
<?php
include_once("config.php");
if(isset($_GET['pro_id']))
{
$id=$_GET['pro_id'];
if(isset($_POST['submitBtn'])) {
$dept_id = $_POST['dept_id'];
$cat_id = $_POST['cat_id'];
/*$pro_id = $_POST['pro_id'];*/
$pro_name = $_POST['pro_name'];
$pro_desc = $_POST['pro_desc'];
$pro_spec = $_POST['pro_spec'];
$pro_price = $_POST['pro_price'];
$status = 'on';
$pro_keywords = $_POST['pro_keywords'];
//image names
$pro_image = $_FILES['pro_image']['name'];
//temp images names
$temp_image = $_FILES['pro_image']['tmp_name'];
if($dept_id=='' OR $cat_id=='' OR $pro_name=='' OR $pro_desc=='' OR $pro_spec=='' OR $pro_price=='' OR $pro_image=='' OR $pro_keywords=='')
{
echo "<script>alert('All the fields are mandatory')</script>";
exit();
}
else
{
//upload image to folder
move_uploaded_file($temp_image,"images/product_images/$pro_image");
$run_query1 = mysqli_query($login, "update products1 SET (dept_id,cat_id,pro_name,pro_desc,pro_spec,pro_price,pro_image,status,date,pro_keywords) values ( '$dept_id','$cat_id','$pro_name','$pro_desc','$pro_spec','$pro_price','$pro_image','$status','NOW()','$pro_keywords' WHERE pro_id='$id'");
if($run_query1)
{
echo "<script>alert('Product updated successfully')</script>";
exit();
}
else
{
echo "<script>alert('Errors')</script>";
}
} }
$query1 = mysqli_query($login, "select * from products1 where pro_id='$id'");
$query2 = mysqli_fetch_array($query1);
?>
這種形式的部分，其中數據從檢索表，當點擊更新按鈕沒有任何反應和頁面重定向查看數據頁面，並顯示舊的數據：
<form action="ViewProduct.php" method="post" enctype="multipart/form-data" name="form1" id="form1">
<table width="650" border="0">
<tr>
<td width="183" align="right">Department:</td>
<th width="231" align="left">
<select name="dept_id" id="dept_id">
<option>Select Department</option>
<?php
$result=dept_show();
while($row=mysqli_fetch_assoc($result))
{
echo "<option value='{$row['dept_id']}'>{$row['dept_name']}</option>";
}
?>
</select></th></tr>
<tr>
<td width="183" align="right">Catagory</td>
<th width="231" align="left">
<select name="cat_id" id="cat_id">
<option>Select Catagory</option>
<?php
$result1=cat_show();
while($row=mysqli_fetch_assoc($result1))
{
echo "<option value='{$row['cat_id']}'>{$row['cat_name']}</option>";
}
?>
</select></th></tr>
<tr>
<!--<td width="231"><input type="hidden" name="pro_id" id="pro_id" value="<t?php echo $pro_id; ?>" /></td>-->
</tr>
<tr>
<td align="right">Product Name/Model:</td>
<td><input type="text" name="pro_name" id="pro_name" value="<?php echo $query2['pro_name']; ?>" /></td>
</tr>
<tr>
<td align="right">Product Description:</td>
<td><textarea type="textarea" name="pro_desc" id="pro_desc" cols="45" rows="5"><?php echo $query2['pro_desc']; ?></textarea></td>
</tr>
<tr>
<td align="right">Products Specification:</td>
<td><textarea type="textarea" name="pro_spec" id="pro_spec" cols="45" rows="5"><?php echo $query2['pro_spec']; ?></textarea></td>
</tr>
<tr>
<td align="right">Product Price:</td>
<td><input type="text" name="pro_price" id="pro_price" value="<?php echo $query2['pro_price']; ?>" /></td>
</tr>
<tr>
<td align="right">Product Image:</td>
<td><input type="file" name="pro_image" id="pro_image" value="<?php echo $query2['pro_image']; ?>" /></td>
</tr>
<tr>
<td></td>
<td><input size="45" type="text" name="text" id="text" value="<?php echo $query2['pro_image']; ?>" /></td>
</tr>
<tr>
<td align="right">Keywords:</td>
<td><input size="45" type="text" name="pro_keywords" id="pro_keywords" value="<?php echo $query2['pro_keywords']; ?>" /></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit" name="submitBtn" id="submit" value="Update" /></td>
</tr>
</table>
</form>
</div> <?php } ?>
</td>
</tr>
</table>
</div>
如何利用這個$ _GET，我有以第一次從表中檢索數據 –
你寫的代碼是不完整的。 prod_id在表單中註釋。它隱藏的領域。每當表單加載時，取消註釋並將值存儲在其中。表單提交時檢查該值。如果存在值，則更新該prod id上的數據否則不存在然後在表 –
中創建新條目根據您的建議，取消註釋表單中的pro_id隱藏字段，但得到相同問題，請幫助 –