2012-01-14 126 views
0

我想要使用2個按鈕(上下)在列表視圖中上下移動,突出顯示每個項目,具體取決於它在列表視圖中的行進方向。通過按鈕向上和向下移動列表視圖

這是我當前的代碼:

Private Sub cmdDown_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdDown.Click 
    If cmdDown.Tag <> totalRecordsReturned Then 
     cmdDown.Tag += 1 
     ListView1.Items(cmdDown.Tag).Selected = True 
     ListView1.Focus() 
    End If 
End Sub 

這不工作它會選擇更多的項目每次我按下按鈕的時間。我能做些什麼來糾正這個問題?

大衛

回答

1

在設計視圖,選擇多選=假

或在代碼中添加這一行

ListView1.MultiSelect = False 

這樣

Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load 
    ListView1.MultiSelect = False 
End Sub 

Private Sub cmdDown_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) _ 
Handles cmdDown.Click 
    If cmdDown.Tag <> totalRecordsReturned Then 
     cmdDown.Tag += 1 
     ListView1.Items(cmdDown.Tag).Selected = True 
     ListView1.Focus() 
    End If 
End Sub 
+1

沒有理由來執行代碼每個'cmdDown_Click'函數執行時間。將其設置在窗體的構造函數中。 – 2012-01-14 17:07:11

+0

根據科迪的建議編輯上述帖子。 – 2012-01-14 17:22:51

0

我想你可以使用此解決方案。使用listview keyup/keydown:

Private Sub lvSearch_KeyDown(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles lvSearch.KeyDown 
     If e.KeyCode = Keys.Down Then 

      If lvSearch.SelectedItems(0).Index < (lvSearch.Items.Count - 1) Then 

       txtName.Text = lvSearch.Items(lvSearch.SelectedItems(0).Index + 1).SubItems(1).Text 

      End If 
     End If 
    End Sub 

    Private Sub lvSearch_KeyUp(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles lvSearch.KeyUp 
     If e.KeyCode = Keys.Up Then 
      If lvSearch.SelectedItems(0).Index >= 0 Then 

       txtName.Text = lvSearch.Items(lvSearch.SelectedItems(0).Index).SubItems(1).Text 

      End If 
     End If 
    End Sub 
0

這是非常有用的,我用它爲我的項目,但它有點不同。我有一個列表視圖,其中第一列是固定索引,因此用戶知道列表中有多少項目,並且可以通過編號引用它們。在上下移動項目時,這是一個問題,因爲第1列中的索引編號需要保持不變並且只更改第2列中的數據。我編寫了下面的類,該類還支持添加,刪除和重命名第2列項目。

Public Class class_ListViewControl 

Public ListViewControl_DebugMode As Boolean = True ' to show exceptions in debug mode 


Public Sub Init_ListView(ByRef SelectedListView As ListView, ByVal FullRowSelect As Boolean, ByVal ViewMode As View, ByVal Columns() As String) 

    ' Pass the list to modify, two common settings and an array of columns by string name 
    Try 

     SelectedListView.View = ViewMode 
     SelectedListView.FullRowSelect = FullRowSelect 

     SelectedListView.Columns.Clear() 

     For i As Integer = 0 To Columns.Length - 1 
      SelectedListView.Columns.Add(Columns(i), -2) 
     Next 

    Catch ex As Exception 
     If ListViewControl_DebugMode = True Then MsgBox(ex.ToString) 
    End Try 


End Sub 

Public Sub MoveListViewItem(ByRef SelectedlistView As ListView, ByVal move As ArrowDirection) 

    ' Pass the listview to edit and the command UP/DOWN 

    Try 
     ' Select between UP/DOWN arrows 
     If move = ArrowDirection.Up And SelectedlistView.SelectedItems.Count > 0 Then 

      Dim selected As ListViewItem = SelectedlistView.SelectedItems(0) 
      Dim indx As Integer = selected.Index 
      Dim totl As Integer = SelectedlistView.Items.Count 

      If indx > 0 Then ' Make sure it's not 0 

       Dim temp As String = SelectedlistView.Items(indx - 1).SubItems(1).Text ' save the string from the old one first so we can put it in the new location 

       ' move the text in column 2 to the column 2 index below it and place the old text in the next column 
       SelectedlistView.Items(indx - 1).SubItems(1).Text = SelectedlistView.Items(indx).SubItems(1).Text 
       SelectedlistView.Items(indx).SubItems(1).Text = temp 

       ' This clears the selection then selects the new index before existing. This allows the user to hit UP again with out having to reselect the item 
       SelectedlistView.SelectedItems.Clear() 
       SelectedlistView.Items(indx - 1).Selected = True 

      End If 


     ElseIf move = ArrowDirection.Down And SelectedlistView.SelectedItems.Count > 0 Then 


      Dim selected As ListViewItem = SelectedlistView.SelectedItems(0) 
      Dim indx As Integer = selected.Index 
      Dim totl As Integer = SelectedlistView.Items.Count 

      If indx < SelectedlistView.Items.Count - 1 Then ' if it's less than the max index you can just move the data to the next one 

       Dim temp As String = SelectedlistView.Items(indx + 1).SubItems(1).Text 

       SelectedlistView.Items(indx + 1).SubItems(1).Text = SelectedlistView.Items(indx).SubItems(1).Text 
       SelectedlistView.Items(indx).SubItems(1).Text = temp 

       ' This clears the selection then selects the new index before existing. This allows the user to hit DOWN again with out having to reselect the item 
       SelectedlistView.SelectedItems.Clear() 
       SelectedlistView.Items(indx + 1).Selected = True 


      End If 

      End If 


    Catch ex As Exception 
     If ListViewControl_DebugMode = True Then MsgBox(ex.ToString) 
    End Try 



End Sub 

Public Sub EditListViewItem(ByRef SelectedListView As ListView, ByVal EditType As Char, ByVal NewText As String) 

    ' Pass the listview to edit, EditType: ADD = 'A' DELETE = 'D', and Index of item 
    Try 

     Dim selected As ListViewItem = Nothing 
     Dim indx As Integer = 0 

     If SelectedListView.SelectedIndices.Count > 0 Then ' Only load if something is selected 
      selected = SelectedListView.SelectedItems(0) 
      indx = selected.Index 
     Else 
      ' This is here because you don't need an index selected to add a new item. 
      selected = Nothing 
      indx = 0 ' set to 0 
     End If 



     Dim total As Integer = SelectedListView.Items.Count 

     Select Case EditType 

      Case "A" ' ADD NEW 

       Dim NewItem As New ListViewItem(CStr(total + 1)) 

       NewItem.SubItems.Add(NewText) 
       SelectedListView.Items.Add(NewItem) 

      Case "D" ' DELETE 
       If selected IsNot Nothing Then ' only execute if something is selected 

        SelectedListView.Items.Remove(selected) ' Delete the selected item 

        For i As Integer = 0 To SelectedListView.Items.Count - 1 
         SelectedListView.Items(i).SubItems(0).Text = CStr(i + 1) 
        Next 


       End If 

      Case "S" ' Save edits 

       SelectedListView.Items(indx).SubItems(1).Text = NewText 

     End Select 

    Catch ex As Exception 
     If ListViewControl_DebugMode = True Then MsgBox(ex.ToString) 
    End Try 


End Sub 

末級

要使用這個類,你的表格1點聲明補充:

Private ListViewClass As New class_ListViewControl 

然後在Form_Load子添加您的初始化:

ListViewClass.Init_ListView(lstv_RFPInfo_Options, True, View.Details, {"#", "Option Title"}) 

添加按鈕例如:

ListViewClass.EditListViewItem(listview1, "A", textbox1.Text) 

刪除按鈕示例:

ListViewClass.EditListViewItem(listview1, "D", "") 

Form 1 example