2013-04-09 61 views
0

我嘗試在Android中的客戶端/服務器端應用程序。我有一個簡單地獲取或發佈數據的PHP文件。在Android上,我有一個從服務器文件獲取和發佈數據的活動。我在訪問它位於c://xampp/htdocs/Project/server.php和android的我有幾行代碼這個文件甲肝問題:在Android中訪問PHP文件FileNotFound異常

URL url = new URL("http://192.178.10.54/xampp/htdocs/Project1/server.php"); 
URLConnection connection = url.openConnection(); 

但是當我運行我的應用程序異常occurres的這些行:

04-09 16:18:21.484: W/System.err(7752):java.io.FileNotFoundException: http://192.178.10.54/xampp/htdocs/Project1/server.php 
04-09 16:18:21.664: W/System.err(7752):  at libcore.net.http.HttpURLConnectionImpl.getInputStream(HttpURLConnectionImpl.java:177) 
04-09 16:18:21.664: W/System.err(7752):  at com.android.ServerInterface.executeHttpRequest(ServerInterface.java:111) 
04-09 16:18:21.664: W/System.err(7752):  at com.android.ServerInterface.getAnimalList(ServerInterface.java:60) 
04-09 16:18:21.664: W/System.err(7752):  at com.android.AndroidListClient$GetListTask.doInBackground(AndroidListClient.java:106) 
04-09 16:18:21.664: W/System.err(7752):  at com.android.AndroidListClient$GetListTask.doInBackground(AndroidListClient.java:1) 
+1

在瀏覽器(鉻,互聯網explorar)打開此:http://192.168.10.54/xampp/htdocs/Project1/server.php告訴我們什麼heppend .. – 2013-04-09 11:28:11

+1

Url喜歡http://192.178.10.54/Project1/server.php – 2013-04-09 11:28:22

+0

@NiravRanpara是的它是192.178.10.54/Project1/server.php ..謝謝 – User42590 2013-04-09 11:31:41

回答

0
URL url = new URL("http://192.168.10.54/xampp/htdocs/Project1/server.php"); 
URLConnection connection = url.openConnection();