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我有兩個輸入字段1.名稱,2.電話。我想要的是(1.當我開始輸入名稱時,它必須從數據庫中搜索自動完成現在,當從搜索查詢中選擇了名稱時,我希望電話輸入在選定名稱的基礎上自動填充 當前我正在使用typeahead .js文件,就能自動搜索名稱如何在第一個字段的輸入的基礎上填寫第二個字段LIVE
我的HTML代碼:
<!DOCTYPE html>
<html lang="en">
<head>
<link href="//maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet">
<script src="//code.jquery.com/jquery-2.1.4.min.js"></script>
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<script src="typeahed.js"></script>
<style>
h1 {
font-size: 20px;
color: #111;
}
.content {
width: 80%;
margin: 0 auto;
margin-top: 50px;
}
.tt-hint,
.Name {
border: 2px solid #CCCCCC;
border-radius: 8px 8px 8px 8px;
font-size: 24px;
height: 45px;
line-height: 30px;
outline: medium none;
padding: 8px 12px;
width: 400px;
}
.tt-dropdown-menu {
width: 400px;
margin-top: 5px;
padding: 8px 12px;
background-color: #fff;
border: 1px solid #ccc;
border: 1px solid rgba(0, 0, 0, 0.2);
border-radius: 8px 8px 8px 8px;
font-size: 18px;
color: #111;
background-color: #F1F1F1;
}
</style>
<script>
$(document).ready(function() {
$('input.Name').typeahead({
name: 'Name',
remote: 'city.php?query=%QUERY'
});
})
</script>
</head>
<body>
<div class="content">
<form>
<h1>Try it yourself</h1>
<input type="text" name="Name" size="30" class="Name" placeholder="Please Enter Name or ZIP code"> </input>
<input type="text" name="Telephone" size="30" class="Telephone" placeholder="Telephone"> </input>
</form>
</div>
</body>
</html>
我的PHP代碼:// 不把數據庫連接部分(很明顯,我已經連接)
<?php
if (isset($_REQUEST['query'])) {
$query = $_REQUEST['query'];
$sql = mysqli_query ($conn,"SELECT Name,Telephone FROM customerdetails WHERE Name LIKE '%{$query}%'");
$array = array();
while ($row = mysqli_fetch_array($sql)) {
$shu[] = array (
'label' => $row['Name'],
'value' => $row['Name'],
);
}
echo json_encode ($shu);
}
?>