嘗試使用結果從一個查詢到在parse.com來自新的查詢結果相結合 - JavaScript的

讓我們看看以下數據：
數據表1：嘗試使用結果從一個查詢到在parse.com來自新的查詢結果相結合 - JavaScript的

item1 item2 
1  1 
1  2 
1  3 
2  1 
2  4

數據表2：

item1 nameItem1 
1  fred 
2  sam

我正在嘗試編寫一個javascript查詢，它將首先根據item2從table1中檢索數據。
然後，它會使用該結果中的item1，並搜索table2作爲名稱。
而對於輸出，我會得到如下：

item2  nameItem1 
1   fred 
1   sam

我用parse.com作爲我的數據庫，我在此慘遭失敗。下面是我的javascript代碼示例：

var className = "seminarAttendance"; //change this to the appropriate class name 

var query = new Parse.Query(className); 

query.equalTo("StudentID", attendancesearch.studentID.value); 

query.find({ 
    success: function(results) { 
     if(results.length==0){ 

     alert("Sorry, there are no results that match your search.") 
      {return;}} 

     var w = window.open(); 
     w.document.write('<html><head><title>Result Table</title>'); 
     w.document.write('<link rel="stylesheet" href="http://netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" type="text/css" >'); 
     w.document.write('<link rel="stylesheet" href="tablesearch.css" type="text/css" />');   
     w.document.write(' </head><body><h3> Here are your search results!</h3><br/>'); 
     w.document.write(' Student # ' + attendancesearch.studentID.value + ' has attended ' +results.length + ' seminars <br>'); 
     w.document.write('<div class="search"><table class="table table-bordered table-condensed table-striped" >'); 
     w.document.write('<thead><tr><td><b>Seminar ID</b></td><td><b>Student ID</b></td><td><b>Time Period</b></td><td><b>Student ID</b></td><td><b>Student ID</b></td></tr></thead><tbody>'); 

     for (var i=0; i < results.length; i++){ 
      var object = results[i]; 

      var semid = object.get("SeminarID"); 
      var studid=object.get("StudentID"); 
      var timeper=object.get("timePeriodID"); 

      var semclass = "seminarTable"; 
      var query2 = Parse.Query(semclass); 
      query2.equalTo("seminarID", semid); 
      query2.first({ 

      success: function(q2object){ 

      var test = q2object.get("seminarName"); 
      }, 
      }); 

      w.document.write('<tr>'); 
      w.document.write('<td>' + semid + '</td>'); 
      w.document.write('<td>' + studid + '</td>'); 
      w.document.write('<td>' + timeper + '</td>'); 
      w.document.write('<td>' + test + '</td>'); 
      w.document.write('</tr>'); 
     } 
     w.document.write('</tbody></table></div></body></html>'); 
     w.document.close();

來源

2014-10-08 David Roberts

您已經在var query2 = Parse.Query（semclass）;中忘記了「new」。它應該是var query2 = new Parse.Query（semclass）; – 2014-10-09 09:45:43

你不能在「for」 loop.Because查詢調用QUERY2需要一定的時間，這比執行「for」循環大得多。相反，您可以獲取「seminarTable」類的所有對象，並將它們存儲在另一個數組中（比如result1）。現在我們有結果和結果1數組，因此您可以手動搜索並放置條件。

var className = "seminarAttendance"; //change this to the appropriate class name 

var query = new Parse.Query(className); 

query.equalTo("StudentID", attendancesearch.studentID.value); 

query.find({ 
    success: function(results) { 
    if(results.length==0){ 

    alert("Sorry, there are no results that match your search.") 
     {return;}} 

    var w = window.open(); 
    w.document.write('<html><head><title>Result Table</title>'); 
    w.document.write('<link rel="stylesheet" href="http://netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" type="text/css" >'); 
    w.document.write('<link rel="stylesheet" href="tablesearch.css" type="text/css" />');   
    w.document.write(' </head><body><h3> Here are your search results!</h3><br/>'); 
    w.document.write(' Student # ' + attendancesearch.studentID.value + ' has attended ' +results.length + ' seminars <br>'); 
    w.document.write('<div class="search"><table class="table table-bordered table-condensed table-striped" >'); 
    w.document.write('<thead><tr><td><b>Seminar ID</b></td><td><b>Student ID</b></td><td><b>Time Period</b></td><td><b>Student ID</b></td><td><b>Student ID</b></td></tr></thead><tbody>'); 




    var semclass = "seminarTable"; 
    var query2 = Parse.Query(semclass); 
    query2.find({ 
     success: function(results1){ 
      //Do whatever you want here 
      w.document.write('<tr>'); 
      w.document.write('<td>' + semid + '</td>'); 
      w.document.write('<td>' + studid + '</td>'); 
      w.document.write('<td>' + timeper + '</td>'); 
      w.document.write('<td>' + test + '</td>'); 
      w.document.write('</tr>'); 
     }, 
     }); 


    } 
    w.document.write('</tbody></table></div></body></html>'); 
    w.document.close();

來源

2015-06-01 11:19:21 Technoid

嘗試使用結果從一個查詢到在parse.com來自新的查詢結果相結合 - JavaScript的

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