如何解析塊可變

Question

我只是想通過文件的列表，並分析其內容打印的文件的名稱後，迭代綁定：執行我 **腳本錯誤時

files: [%test1.txt %test2.txt] 
rule: [to "test" thru "test" copy x to "." (print x print file)] 
foreach file files [ 
    content: read file 
    parse [any rule] 
] 

：文件沒有值

如何將文件var名稱綁定到規則塊程序的上下文？

Answer 1

只需要綁定規則中的每個迭代：

files: [%test1.txt %test2.txt] 
rule: [to "test" thru "test" copy x to "." (print x print file)] 
foreach file files [ 
    bind rule 'file 
    content: read file 
    parse content [any rule] 
] 

Answer 2

也可以做這樣（把在規則的字面，讓FOREACH它在正確的時間綁定）：

files: [%test1.txt %test2.txt] 
rule: [to "test" thru "test" copy x to "." (print x print file)] 
foreach file files compose/only/deep [ 
    content: read file 
    parse content [any (rule)] 
]