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這是我當前的代碼。我想檢查兩個值(行)來檢查文件中的匹配項。匹配索引值
def checkOS():
fid1 = open("C:/Python/NSRLOS.txt", 'r')
fid2 = open("C:/Python/sha_sub_hashes.out", 'r')
outdata = open("osMatches.txt", 'w')
line1 = fid1.readline()
line2 = fid2.readline()
while(line1 and line2):
xline= line1.split(',')[1]
yline = line2.split("|")[3]
zline = xline.replace('"','')
if (yline == zline):
outdata.append([yline , zline])
print xline, zline
if __name__=="__main__":
checkOS()
唯一的問題是我不知道我寫那有什麼,if語句之前,所有的代碼只是重新格式化,以便能夠從該行的指數拉。我想知道的是,如果我使用的陳述在這個意義上是有效的並且是有效的?然後我想輸出相等的值。 下面是在文件中的某些行:
file2:
"10","Amstrad 6128","Unknown","1006"
"100","Macintosh 9.0","8.5.1","67"
"101","Macintosh 9.0.4","na","67"
"102","Macintosh 9.1","9.1","67"
"103","Macintosh 9.2","9.2","67"
"104","Macintosh 9.2.2","9.2.2","67"
"105","Macintosh 9.x","9.X","67"
"106","Macintosh X","10","67"
"107","Macintosh7.5.3","7.5.3","67"
"108","NetWare","n/a","674"
"109","Novel Dos 7.0","7","609"
"11","Apple II+","Unknown","67"
"110","OS/2","Unknown","427"
file2:
DD84270022E57F1850C8454FA432ADFF99588157B|index.docbook|2225|Redhat 7.3 (32bit)|Linux
D84270022E57F1850C8464F5432ADFF99588157B|index.docbook|2225|Redhat 8.0 (32bit)|Linux
26EEEB25D7005F9FF9EE05A8084C77242702FBAD|Localizable.strings|2142|Mac OS X 10.4|OSX
34DC3D728C34E32F090307F575254D57E53C53FF|SYSTEM|10747904|Windows 7 Home Premium (32bit)|Windows
279E5A766C88EEA5AB946A0AF8D0C4FC366B2AF9|totem.devhelp|21324|Linux Ubuntu Desktop 9.10 (32bit)|Linux
279E5A766C88EEA5AB964A0AF8D0C4FC366B2AF9|totem.devhelp|21324|Linux Ubuntu Desktop 9.10 (64bit)|Linux
B3D11390AB8683BBE443A415EDD91BFDFD482134|dslconfig.pyc|6246|Redhat 9.0 (32bit)|Linux
現在,你可能不會發現這幾行任何直接的比賽,但我知道,下了線的地方就會有至少一個比賽,因爲我看到了同時瀏覽文件。
你能給出一個來自每個文件的樣本行,應該被認爲是等效的或不等效的嗎? – mVChr 2012-07-09 17:14:48
你有一個無限循環。 – mgilson 2012-07-09 17:17:04
而代碼會在if中產生'AttributeError'。 – 2012-07-09 17:19:30