如何從ios中的字符串響應中創建數組或字典？

我正在爲ios應用程序調用php webservice。我收到如下字符串的迴應;如何從ios中的字符串響應中創建數組或字典？

一個：10：{S：11：「sso_user_id」; S：6：」 123456」 ; S：9：」姓名」; S：3：」 XYZ」，S：8：」姓氏」 S：3：」 ABC」; S：5：」 abono」; S：1：」 1」 ; S：4：」散列「; S：32：」 638550add0b538a5a771d 「; S：5：」令牌「; S ：32：「78451add0b51245789555514585」; S：5：「登錄」; S：8：「XXXXXXXX」; S：6：「曲奇」; S：0：「」; S：6：「訪問」;一個：5： {S：4：「角色」; S：6：「測試」; S：13：」initial_reads「; S：1：」8「; S：14：」reads_remained「; S：1：」8「; S ：11：「valid_until」; S：9：「2014年11月1日」; S：10：「tmp_portal」; S：10：「google.com」;} S：5：「錯誤」; S：0：「」;}

......鍵.........和...........值

sso_user_id  123456 
firstname  xyz 
lastname  abc 
abono   1 
hash   638550add0b538a5a771d 
token   78451add0b51245789555514585 
login   xxxxx 
role   TESTER 
initial_reads 11 
valid_until  2014-11-1 
tmp_portal  google.com

注意：其中：10表示10個對象的數組，s：11表示長度爲10個字符的字符串。

但我沒有任何想法如何將此字符串轉換爲數組或字典來獲取鍵值。

感謝，

來源

2014-10-27 Rohan

爲什麼你使用字符串作爲響應，使用JSON輕鬆實現。 – 2014-10-27 04:36:06

@KumarKL，但我沒有得到JSON格式的響應。 API由第三方製作。所以我不能告訴他們改變爲JSON響應 – Rohan 2014-10-27 04:37:51

我可以看到一種可能性，即搜索'「」'並將字符串值視爲鍵和值。請使用 – 2014-10-27 04:41:32

最後我用以下解決我的問題。我在這裏發佈我的代碼，以便其他任何人都可以解決像我這樣的問題;

//在ParsedData.h

#import <Foundation/Foundation.h> 

@interface ParsedData : NSObject 
{ 

} 
@property(nonatomic,retain)NSMutableArray *parsedDataArr; 
@property(nonatomic,retain)NSMutableDictionary *finalDict; 

@end

//在ParsedData.m

#import "ParsedData.h" 

@implementation ParsedData 

@synthesize parsedDataArr; 

-(id)init 
{ 
    parsedDataArr = [[NSMutableArray alloc]initWithObjects:@"sso_user_id",@"firstname", @"lastname",@"abono",@"hash",@"token",@"login",@"cookie",@"role",@"initial_reads",@"reads_remained",@"valid_until",@"tmp_portal",@"error",nil]; 

    return self; 
}

//你ViewVontrller.m ..

#imprort「ParsedData.h」

-(void)buildDataFromString:(NSString*)stringToBuild; 
{ 
    ParsedData *pd = [[ParsedData alloc]init]; 

    pd.finalDict = [[NSMutableDictionary alloc]init]; 

    for (int i =0; i < pd.parsedDataArr.count; i++) 
    { 
     NSString *arrKey = [pd.parsedDataArr objectAtIndex:i]; 

     if ([stringToBuild rangeOfString:arrKey].location != NSNotFound) 
     { 
      int length = 0; 

      NSString *subString = [stringToBuild substringFromIndex:[stringToBuild rangeOfString:arrKey].location + arrKey.length + 2]; 

      if ([arrKey isEqualToString:@"initial_reads"] || [arrKey isEqualToString:@"reads_remained"]) 
      { 
       length = [self getIntLengthValue:subString]; 

       [pd.finalDict setValue:[NSNumber numberWithInt:length] forKey:arrKey]; 

      } 
      else 
      { 
       length = [self getStringLengthValue:subString]; 

       if (length == 0) 
       { 
        [pd.finalDict setValue:@"" forKey:arrKey]; 
       } 

       else 
       { 
        // Gets the string inside the first set of parentheses in the regex 
        NSString *inside = [self getKeyValue:subString]; 

        [pd.finalDict setValue:inside forKey:arrKey]; 
       } 
      } 
     } 
    } 

    NSLog(@"final parsed values dict - %@",pd.finalDict); 
} 

-(int)getIntLengthValue:(NSString *)subString 
{ 
    NSRegularExpression *regex1 = [NSRegularExpression 
            regularExpressionWithPattern:@"\"(.+?)\"" options:0 error:NULL]; 

    NSTextCheckingResult *result = [regex1 firstMatchInString:subString 
                 options:0 range:NSMakeRange(0, [subString length])]; 

    NSString *str =[subString substringWithRange:[result rangeAtIndex:1]]; 

    NSCharacterSet *alphaNums = [NSCharacterSet decimalDigitCharacterSet]; 
    NSCharacterSet *inStringSet = [NSCharacterSet characterSetWithCharactersInString:str]; 
    BOOL isDigitOnly = [alphaNums isSupersetOfSet:inStringSet]; 

    if (isDigitOnly) 
    { 
     return [str intValue]; 
    } 
    else 
    { 
     return 0; 
    } 
} 

-(int)getStringLengthValue:(NSString *)subString 
{ 
    NSRegularExpression *regex1 = [NSRegularExpression 
            regularExpressionWithPattern:@":(.+?):" options:0 error:NULL]; 

    NSTextCheckingResult *result = [regex1 firstMatchInString:subString 
                 options:0 range:NSMakeRange(0, [subString length])]; 

    NSString *str =[subString substringWithRange:[result rangeAtIndex:1]]; 

    int length = [str intValue]; 

    return length; 
} 

-(NSString *)getKeyValue:(NSString *)subString 
{ 
    NSRegularExpression *regex = [NSRegularExpression 
            regularExpressionWithPattern:@"\"(.+?)\"" options:0 error:NULL]; 

    NSTextCheckingResult *result = [regex firstMatchInString:subString 
                options:0 range:NSMakeRange(0, [subString length])]; 

    // Gets the string inside the first set of parentheses in the regex 
    NSString *inside = [subString substringWithRange:[result rangeAtIndex:1]]; 

    return inside; 
}

來源

2014-10-30 06:50:28 Rohan

Well.It是很容易得到this.If你按照下面的編碼

//just give your URL instead of my URL 

    NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:[NSURL  URLWithString:@"http://api.worldweatheronline.com/free/v1/search.ashx?query=London&num_of_results=3&format=json&key=xkq544hkar4m69qujdgujn7w"]]; 

    [request setHTTPMethod:@"GET"]; 

    [request setValue:@"application/json;charset=UTF-8" forHTTPHeaderField:@"content-type"]; 

    NSError *err; 

    NSURLResponse *response; 

    NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err]; 

//You need to check response.Once you get the response copy that and paste in ONLINE JSON VIEWER.If you do this clearly you can get the correct results.  

//After that it depends upon the json format whether it is DICTIONARY or ARRAY 

    NSDictionary *jsonArray = [NSJSONSerialization JSONObjectWithData:responseData options: NSJSONReadingMutableContainers error: &err]; 

    NSArray *array=[[jsonArray objectForKey:@"s"]objectForKey:@"sso_user_id "]objectForKey:@"firstname"]objectForKey:@"lastname"]objectForKey:@"abono"]objectForKey:@"hash"]objectForKey:@"token"]objectForKey:@"login"]objectForKey:@"role "]objectForKey:@"initial_reads"]objectForKey:@"valid_until"]objectForKey:@"tmp_portal"]; // Now i give your key all keys.So check it.

來源

2014-10-27 04:49:30 user3182143

而不是objectForKey這樣的解決方法，您還可以爲valueForKey提供valueForKey。 – user3182143 2014-10-27 04:52:32

我沒有得到JSON格式的響應，我正在使用WSDL webservice，即通過xml解析 – Rohan 2014-10-27 05:02:28

k.I現在將幫助您。 – user3182143 2014-10-27 05:04:22

在您的.h部分

//第1步：添加代表類

First of all you should add <NSXMLParserDelegate>

//第2步：創建必要的對象

NSXMLParser *parser; 
    NSMutableData *ReceviedData; 
    NSMutableString *currentStringValue; 

    NSMutableArray *sso_user_id; 
    NSMutableArray *firstName; 
    NSMutableArray *lastName; 
    NSMutableArray *abono; 
    NSMutableArray *hash; 
    NSMutableArray *token; 
    NSMutableArray *login; 
    NSMutableArray *role; 
    NSMutableArray *initial_reads; 
    NSMutableArray *valid_until; 
    NSMutableArray *tmp_portal;

在您的m部分

//Step 3 - Allocate your all Arrays in your viewDidLoad method 

    sso_user_id = [NSMutableArray alloc]init]; 
    .... 
    tmp_portal = [NSMutableArray alloc]init]; 

//Step 4 - Create Connection in your viewDidLoad Like 

    [self createConnection:@"http://www.google.com"];//give yoyur valid url. 

- (void)createConnection:(NSString *)urlString 
{ 
    NSURL *url = [NSURL URLWithString:urlString]; 

    //Step 5 - parser delegate methods are using NSURLConnectionDelegate class or not. 
    BOOL success; 
    if (!parser) 
    { 
    parser = [[NSXMLParser alloc] initWithContentsOfURL:url]; 
    parser.delegate = self; 
    parser.shouldResolveExternalEntities = YES; 
    success = [parser parse]; 
    NSLog(@"Success : %c",success); 
    } 
} 
-(void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict 
{ 
    NSLog(@"Current Element Name : %@",elementName); 

    if ([elementName isEqualToString:@"sso_user_id"]) 
    { 
    NSLog(@"The sso_user_id is==%@",elementName); 
    } 
    if ([elementName isEqualToString:@"firstName"]) 
    { 
    NSLog(@"The firstname is==%@",elementName); 
    } 
    if ([elementName isEqualToString:@"lastName"]) 
    { 
    NSLog(@"The lastname is==%@",elementName); 
    } 
} 
-(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string 
{ 
    currentStringValue = [[NSMutableString alloc] initWithString:string]; 
    NSLog(@"Current String Value : %@",currentStringValue); 
} 
-(void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName 
{ 
    if ([elementName isEqualToString:@"sso_user_id"]) 
    { 
    [sso_user_id addObject:currentStringValue]; 
    } 
    if ([elementName isEqualToString:@"firstName"]) 
    { 
    [firstName addObject:currentStringValue]; 
    } 
    if ([elementName isEqualToString:@"lastName"]) 
    { 
    [lastName addObject:currentStringValue]; 
    } 
    currentStringValue = nil; 
}

來源

2014-10-27 05:43:14 user3182143

我沒有像這樣得到回覆。我得到整個響應字符串中的方法** - （無效）解析器：（NSXMLParser *）解析器foundCharacters：（NSString *）字符串**而不是元素由元素 – Rohan 2014-10-27 05:49:34

你應該按照這種方式。否則很難得到響應羅漢。 – user3182143 2014-10-27 05:51:49

如果你想要字符串，使用字符串，而不是數組。獲取字符串中的值。 – user3182143 2014-10-27 05:53:18

如何從ios中的字符串響應中創建數組或字典？

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