比較jsonb中的2個數組成員數

Question

有列（User_ID，A_D）的表。 A_D列是jsonb。

User_ID | A_D 
1 | "{"agreements": [1, 7], "disagreements": [13]}" 
2 | "{"disagreements": [13, 100]}" 
4 | "{"agreements": [14, 177, 22], "disagreements": [3, 2]}" 
5 | "{"agreements": [77]}" 
6 | "{"agreements": [24, 14, 89, 102], "disagreements": [200]}" 

我需要讓用戶，誰在「協議」陣列更多的成員比「分歧」陣列。

這些用戶ID必須返回

1 
4 
5 
6 

Answer 1

如果我理解正確的，你需要這樣的：

select t1.User_ID, t1.cnt, t2.cnt from (
    select User_ID, count(*) as cnt from ( 
     select User_ID, jsonb_array_elements_text(a_d->'agreements') from your_table 
    ) arr1 
    GROUP BY User_ID 
) t1 
LEFT JOIN (
    select User_ID, count(*) as cnt from ( 
     select User_ID, jsonb_array_elements_text(a_d->'disagreements') from your_table 
    ) arr2 
    GROUP BY User_ID 
) t2 
ON t1.User_ID = t2.User_ID 
where coalesce(t1.cnt, 0) > coalesce(t2.cnt, 0) 

Answer 2

隨着json[b]_array_length() function(s)，它是那樣簡單：

WHERE jsonb_array_length(A_D -> 'agreements') 
    > jsonb_array_length(A_D -> 'disagreements')