從另一個視圖中關閉UIPopoverController

Question

我在另一個視圖中有一個UIPopoverController命名爲popover。我想知道的是，如果在當前彈出窗口視圖中按下了UIButton，我該如何解除彈出窗口？提前致謝。

Answer 1

您可以使用NSNotification來告訴其他視圖忽略它的彈出視圖。

用法示例：

// Add an observer that will respond to our notification. 
[[NSNotificationCenter defaultCenter] addObserver:self // <- This is the object that will has the selector that we want to run (the same one we use in the next line). 
             selector:@selector(doSomething:) // <- This is the selector we want to run. 
              name:@"doSomethingNow" // <- This is notification name we will send to activate our observer's selector. 
              object:nil]; // Don't worry about this for now. 


// Post the notification. This has the same name as our observer above, so our 'doSomething' selector should be run. 
[[NSNotificationCenter defaultCenter] postNotificationName:@"doSomethingNow" object:nil]; 


// the function specified in the same class where we defined the addObserver 
- (void)doSomething:(NSNotification *)pNotification { 
    NSLog(@"Received Notification..."); 
} 

Answer 2

我一直覺得很奇怪，一個UIViewController知道它應該有多大的酥料餅通過它的「contentSizeForViewInPopover」屬性，但指針不保留到UIPopoverController本身。我總是最後加入：

@property (nonatomic,assign) UIPopoverController* popover; 

我的UIViewController類，並設置，當創建popover。然後從該UIViewController中的任何東西，我可以這樣做來解僱popover：

[popover dismissPopoverAnimated:YES];