我想從一個類中的方法動態創建模塊級功能。因此,對於類中的每個方法,我想創建一個具有相同名稱的函數來創建該類的一個實例,然後調用該方法。如何從一個類中的方法動態創建模塊級功能
我想這樣做的原因是我可以採用面向對象的方法來創建Fabric文件。由於Fabric將調用模塊級功能,但不能調用類的方法,所以這是我的解決方法。
我已經使用了以下鏈接讓我開始
- How do I get list of methods in a Python class?
- dynamically adding functions to a Python module
- How do I call setattr() on the current module?
- http://effbot.org/zone/python-getattr.htm
- Calling a function of a module from a string with the function's name in Python
- How to modify the local namespace in python
,我想出了下面的代碼
import inspect
import sys
import types
class TestClass(object):
def __init__(self):
pass
def method1(self, arg1):
print 'method 1 %s' % arg1
def method2(self):
print 'method 2'
def fabric_class_to_function_magic(module_name):
# get the module as an object
print module_name
module_obj = sys.modules[module_name]
print dir(module_obj)
# Iterate over the methods of the class and dynamically create a function
# for each method that calls the method and add it to the current module
for method in inspect.getmembers(TestClass, predicate=inspect.ismethod):
print
print method
method_name, method_obj = method
# create a new template function which calls the method
def newfunc_template(*args, **kwargs):
tc = TestClass()
func = getattr(tc, method_name)
return func(*args, **kwargs)
# create the actual function
print 'code: ', newfunc_template.func_code
print 'method_name: ', method_name
newfunc = types.FunctionType(newfunc_template.func_code,
{'TestClass': TestClass,
'getattr': getattr,
'method_name': method_name,
},
name=method_name,
argdefs=newfunc_template.func_defaults,
closure=newfunc_template.func_closure,
)
# add the new function to the current module
setattr(module_obj, method_name, newfunc)
# test the dynamically created module level function
thismodule = sys.modules[__name__]
print dir(thismodule)
fabric_class_to_function_magic(__name__)
print dir(thismodule)
method1('arg1')
method2()
而且我得到以下錯誤
['TestClass', '__builtins__', '__doc__', '__file__', '__name__', '__package__', 'fabric_class_to_function_magic', 'inspect', 'sys', 'thismodule', 'types']
__main__
['TestClass', '__builtins__', '__doc__', '__file__', '__name__', '__package__', 'fabric_class_to_function_magic', 'inspect', 'sys', 'thismodule', 'types']
('__init__', <unbound method TestClass.__init__>)
code: <code object newfunc_template at 0x7f8800a28d50, file "test.py", line 85>
method_name: __init__
('method1', <unbound method TestClass.method1>)
code: <code object newfunc_template at 0x7f8800a28d50, file "test.py", line 85>
method_name: method1
('method2', <unbound method TestClass.method2>)
code: <code object newfunc_template at 0x7f8800a28d50, file "test.py", line 85>
method_name: method2
['TestClass', '__builtins__', '__doc__', '__file__', '__init__', '__name__', '__package__', 'fabric_class_to_function_magic', 'inspect', 'method1', 'method2', 'sys', 'thismodule', 'types']
Traceback (most recent call last):
File "test.py", line 111, in <module>
method1('arg1')
File "test.py", line 88, in newfunc_template
return func(*args, **kwargs)
TypeError: method2() takes exactly 1 argument (2 given)
這似乎是重用參考功能?有任何想法嗎?
更新:這裏是斯內德爾德的修復工作代碼
def fabric_class_to_function_magic(module_name):
# get the module as an object
module_obj = sys.modules[module_name]
# Iterate over the methods of the class and dynamically create a function
# for each method that calls the method and add it to the current module
for method in inspect.getmembers(TestClass, predicate=inspect.ismethod):
method_name, method_obj = method
# get the bound method
tc = TestClass()
func = getattr(tc, method_name)
# add the function to the current module
setattr(module_obj, method_name, func)
更新2:這是我關於這個問題的博客文章:http://www.saltycrane.com/blog/2010/09/class-based-fabric-scripts-metaprogramming-hack/
奇怪的是,你還應該設置'func .__ module__ = module_name'以便它能正確地描述它自己,否則它會報告它的模塊是包含'fabric_class_to_function_magic'而不是目標模塊的模塊! – F1Rumors 2017-12-01 20:10:00