Ruby構建和返回哈希

我是Ruby新手，正在嘗試一些簡單的練習來弄清楚它是如何工作的。目前我正在嘗試對一個字符串進行排序，找出每個字母在字符串中有多少個字符，然後在散列中返回這些值。一旦我獲得了散列中的所有值，我希望能夠用其他方法修改該數據。Ruby構建和返回哈希

require 'pp' 

    def countLetters 
     #creating variables for processing 
     start = "If debugging is the process of removing software bugs, then programming must be the process of putting them in." 
     alph = "abcdefghijklmnopqrstuvwxyz" 
     output = alph.each_char do |i| 
     char = alph[i] 

     # moving all letters to lower case 
     num = start.downcase.count i 
     # pass the char and value into a hash 
      if num >= 1 
      #puts "#{char} = #{num}" 
      return [{:letter => char, :value => num}] 
     end 
     end 
    end 

    pp countLetters

我能得到它返回的第一個值，但我似乎無法弄清楚如何在方法迭代，直到我收到無返回值2,3,4等。任何幫助，這將是偉大的。我完全使用pp來觀察我的值返回。

來源

2015-04-07 SirGed

用p代替第15行的返回似乎打印其餘的值。 return導致它退出each_char循環

來源

2015-04-07 05:15:22 6ameDev

我明白這一點，將更好的方法來做到這一點是在循環內建立哈希然後返回整個哈希？使用類似 hash = Hash.new hash.store {input} return hash – SirGed

我想通了。我正在錯誤地構建散列。以下是我如何解決這個問題。

require 'pp' 

    def countLetters 
     #creating variables for processing 
     start = "If debugging is the process of removing software bugs, then programming must be the process of putting them in." 
     alph = "abcdefghijklmnopqrstuvwxyz" 
     output = Hash.new 
     alph.each_char do |i| 
     char = alph[i] 
     # moving all letters to lower case 
     num = start.downcase.count i 
     # pass the char and value into a hash 
     if num >= 1 
      #puts "#{char} = #{num}" 
      output.store (char) , (num) 
     end 
     end 
     return output 
    end 

    pp countLetters

來源

2015-04-07 16:46:13 SirGed

Ruby構建和返回哈希

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