除去空間中的字符串

Question

特定字符後，我有一個從服務器來的字符串：

<p>Test iOS Contact &nbsp;<a href=\"tel:(945) 369-8563\">(945) 369-8563</a></p> 

我想它出現在電話號碼10個字符電話後刪除任何空間。

我正在使用下面的代碼。

if ([serviceMessage containsString:@"tel:"]) { 
       NSUInteger location = [serviceMessage rangeOfString:@"tel:"].location + 4; 
    serviceMessage = [serviceMessage substringFromIndex:location]; 
    [serviceMessage substringWithRange:NSMakeRange(11,0)]; 
    serviceMessage =[serviceMessage substringToIndex:10]; 
    NSLog(@"New Trimed string:%@",serviceMessage); 
    serviceMessage = [serviceMessage stringByReplacingOccurrencesOfString:@" " withString:@""]; 
    NSLog(@"Final Trimed string:%@",serviceMessage); 
             } 

Answer 1

有代碼來做到這一點

NSString * serviceMessage = @"<p>Test iOS Contact &nbsp;<a href=\"tel:(945) 369-8563\">(945) 369-8563</a></p>"; 
NSArray *arr = [serviceMessage componentsSeparatedByString:@":"]; 

NSString * newStr = [[arr objectAtIndex:1] stringByReplacingOccurrencesOfString:@" " withString:@""]; 
NSString * updatedString = [NSString stringWithFormat:@"%@%@",[arr firstObject],newStr]; 

希望它能幫助:)

Answer 2

-(NSString *)removeSpacseFromPhoneNumber:(NSString *)string 
{ 
    NSString *resultString = @""; 
    NSString *phoneIndicatorString = @"tel:"; 

    NSRange range = [string rangeOfString:phoneIndicatorString]; 
    if (range.location == NSNotFound) { 
     NSLog(@"String does not contain tel:"); 
     return nil; 
    } 

    resultString = [string substringToIndex:range.location + phoneIndicatorString.length]; // copy up to and including tel: 
    NSString *phoneString = [string substringFromIndex:range.location + phoneIndicatorString.length + 1]; // copy from after tel: 
    NSString * convertedPhoneString = [phoneString stringByReplacingOccurrencesOfString:@" " withString:@""]; 

    return [resultString stringByAppendingString:convertedPhoneString]; 
} 

你可以調用這個：

NSString *result = [self removeSpacseFromPhoneNumber:yourString];