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我正在開發一個簡單的學生信息應用程序。我的index.phtml中有學生名單,我可以在那裏編輯學生信息。它工作的很好,但我想用版本學生信息模態。但我不知道該怎麼辦this.Below我已經發布我的最新代碼:如何使用jQuery的簡單模態插件來編輯zend框架中的表單數據?
/// indexController.php
public function editAction()
{
$modelStudents = new Application_Model_DbTable_Students();
$id = (int) $this->_getParam('id');
$student = $modelStudents->fetch($id);
$form = new Application_Form_Student($student->email);
$form->submit->setLabel('Save');
$this->view->form = $form;
if ($this->getRequest()->isPost()) {
$formData = $this->getRequest()->getPost();
if ($form->isValid($formData)) {
$id = (int)$form->getValue('id');
$name = $form->getValue('name');
$email = $form->getValue('email');
$phone = $form->getValue('phone');
$students = new Application_Model_DbTable_Students();
$students->updateStudent($id, $name, $email, $phone);
$this->_helper->redirector('index');
} else {
$form->populate($formData);
}
} else {
$id = $this->_getParam('id', 0);
if ($id > 0) {
$form->populate($modelStudents->getStudent($id));
}
}
}
/// index.phtml
<html>
<head>
<style type="text/css" rel="stylesheet">
</style>
<script type="text/javascript" src="jQuery.js"> </script>
<script type ="text/javascript" src="jquery.simplemodal-1.4.2.js" ></script>
<script>
<?php
echo "Student List";
?>
<p><a href="<?php echo $this->url(array('controller'=>'index',
'action'=>'add'));?>">Add new student</a></p>
<table border="1">
<tr>
<th>Name</th>
<th>Email</th>
<th>Phone</th>
<th>Action</th>
</tr>
<?php foreach($this->students as $student) : ?>
<tr>
<td><?php echo $student->name;?></td>
<td><?php echo $student->email;?></td>
<td><?php echo $student->phone;?></td>
<td>
<a href="<?php echo $this->url(array('controller'=>'index',
'action'=>'edit', 'id'=>$student->id));?>">Edit</a>
<a href="<?php echo $this->url(array('controller'=>'index',
'action'=>'delete', 'id'=>$student->id));?>">Delete</a>
<p id="delete" > Delete </p>
</td>
</tr>
<?php endforeach; ?>
</table>
</center>
</html>
////edit.phtml
<center>
<?php
echo "Edit Student List ";
echo $this->form ;
?>
</center>
請讓我知道如何使用jQuery簡單模態插件來完成此任務。 在此先感謝
這個問題有點含糊,涉及到相當多的編碼。我建議你先看看AJAX和jQuery教程。之後,如果你有一些具體問題,我會更樂意幫助你。 – 2012-07-30 13:56:57