的Open XML插件 - SQL 2005

Question

我有哪裏我傳遞一個簡單的XML存儲過程：

'<Products><ProductId>1</ProductId><ProductId>2</ProductId></Products>' 

我有一個@temp表中的SQL具有ProductID列：

DECLARE @Temp TABLE (
ProductId NVARCHAR(10) 
)  

我需要編寫一個insert語句，它將遍歷XML中的ProductId（可以是無限的）並繼續插入（在@temp表中），直到XML沒有剩下的ProductId節點。

涉及遊標的解決方案是不可行的！

以下是我試圖執行代碼：

Declare @test XML 
SET @test = '<Products><ProductId>1</ProductId><ProductId>2</ProductId></Products>' 
DECLARE @Temp TABLE(  
    ProductId NVARCHAR(10) 
    ) 
INSERT INTO @Temp(ProductId) 
SELECT tab.col.value('./ProductId[1]','NVARCHAR(10)') AS 'ProductId' 
FROM @test 
CROSS APPLY 
xml_data.nodes('//Products') AS tab(col) 

我不斷收到錯誤：

Must declare the table variable "@test". 

Answer 1

DECLARE @test XML 
    SET @test = '<Products><ProductId>1</ProductId><ProductId>2</ProductId></Products>' 

DECLARE @Temp TABLE(ProductId NVARCHAR(10)) 

DECLARE @docHandle int 
EXEC sp_xml_preparedocument @docHandle OUTPUT, @doc 

INSERT INTO @Temp(ProductId) 
    SELECT t.value('./ProductId[1]','NVARCHAR(10)') AS 'ProductId' 
     FROM OPENXML(@docHandle, '//Products', 1) t 

EXEC sp_xml_removedocument @docHandle 

Answer 2

你可以把XML轉換成另一種臨時表，然後做一個INSERT語句從那裏：

http://www.lockergnome.com/sqlsquirrel/2008/05/23/how-to-turn-imported-xml-into-a-relational-format-in-sql-server-2005/

Answer 3

DECLARE @idoc int 

DECLARE @doc varchar(1000) 

SET @doc =' 
<OutLookContact> 
<Contact FirstName="Asif" LastName="Ghafoor" EmailAddress1="asifghafoor@my.web.pk" /> 
<Contact FirstName="Rameez" LastName="Ali" EmailAddress1="rameezali@my.web.pk" /> 
<Contact FirstName="Aneel" LastName="Maqsood" EmailAddress1="aneelmaqsood@my.web.pk" /> 
</OutLookContact>' 

--Create an internal representation of the XML document. 

EXEC sp_xml_preparedocument @idoc OUTPUT, @doc 

-- Execute a SELECT statement that uses the OPENXML rowset provider. 

DECLARE @Temp TABLE(FirstName VARCHAR(250),LastName VARCHAR(250),Email1 VARCHAR(250)) 

INSERT INTO @Temp(FirstName,LastName,Email1) 



SELECT * 

FROM OPENXML (@idoc, '/OutLookContact/Contact',1) 

WITH (FirstName varchar(50),LastName varchar(50),EmailAddress1 varchar(50)) 


select FirstName,LastName,Email1 from @Temp