應用程序無法訪問電話簿

Question

我忍受了好幾天，試圖訪問名稱和電話號碼簿，全部失敗。我使用了以下代碼，該代碼在測試應用程序中成功運行，但是當我將它添加到項目工作中時，它不起作用。 「授予」變量不斷具有值 - 「錯誤」，並且出現「訪問失敗」錯誤。儘管如此，在隱私設置不顯示滑塊允許訪問... 我早已找不到的答案，一個相當奇怪的行爲...

我會感謝任何幫助！`

CNContactStore *store = [[CNContactStore alloc] init]; 
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) { 
    if (granted == YES) { 

     NSMutableArray *contacts = [NSMutableArray array]; 

     NSArray *keys = @[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactPhoneNumbersKey, CNContactImageDataKey]; 
     NSString *containerId = store.defaultContainerIdentifier; 
     NSPredicate *predicate = [CNContact predicateForContactsInContainerWithIdentifier:containerId]; 
     NSError *error; 
     NSArray *cnContacts = [store unifiedContactsMatchingPredicate:predicate keysToFetch:keys error:&error]; 
     if (error) { 
      NSLog(@"error fetching contacts %@", error); 
     } else { 
      for (CNContact *contact in cnContacts) { 

       TSContact *newContact = [[TSContact alloc] init]; 
       newContact.firstName = contact.givenName; 
       newContact.lastName = contact.familyName; 
       UIImage *image = [UIImage imageWithData:contact.imageData]; 
       newContact.image = image; 
       for (CNLabeledValue *label in contact.phoneNumbers) { 
        NSString *phone = [label.value stringValue]; 
        if ([phone length] > 0) { 
         [contacts addObject:phone]; 
        } 
       } 
      } 
     } 
    } else { 
     NSLog(@"Error = %@", error.localizedDescription); 
    } 
}]; 

Answer 1

如果你想操作以訪問現有的聯繫人的信息，在你的地址簿中的代碼可以幫助你:)

步驟1：添加

#import <AddressBook/AddressBook.h> 

步驟2：呼叫從viewDidLoad中

-(void)phonenumber 
{ 
    self.navigationController.navigationBarHidden = true; 
    ABAuthorizationStatus status = ABAddressBookGetAuthorizationStatus(); 

    if (status == kABAuthorizationStatusDenied || status == kABAuthorizationStatusRestricted) { 
     // if you got here, user had previously denied/revoked permission for your 
     // app to access the contacts, and all you can do is handle this gracefully, 
     // perhaps telling the user that they have to go to settings to grant access 
     // to contacts 

     [[[UIAlertView alloc] initWithTitle:nil message:@"This app requires access to your contacts to function properly. Please visit to the \"Privacy\" section in the iPhone Settings app." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show]; 
     return; 
    } 

    CFErrorRef error = NULL; 
    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error); 

    if (!addressBook) { 
     NSLog(@"ABAddressBookCreateWithOptions error: %@", CFBridgingRelease(error)); 
     return; 
    } 

    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) { 
     if (error) { 
      NSLog(@"ABAddressBookRequestAccessWithCompletion error: %@", CFBridgingRelease(error)); 
     } 

     if (granted) { 
      // if they gave you permission, then just carry on 
      [self listPeopleInAddressBook:addressBook]; 
     } else { 
      // however, if they didn't give you permission, handle it gracefully, for example... 
      dispatch_async(dispatch_get_main_queue(), ^{ 
       // BTW, this is not on the main thread, so dispatch UI updates back to the main queue 
       [[[UIAlertView alloc] initWithTitle:nil message:@"This app requires access to your contacts to function properly. Please visit to the \"Privacy\" section in the iPhone Settings app." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show]; 
      }); 
     } 
     CFRelease(addressBook); 
    }); 
    // Do any additional setup after loading the view. 
} 

步驟3以下方法：也加入這個方法將你的代碼 這種方法可以讓你的特定聯繫人的所有必需的信息。

- (void)listPeopleInAddressBook:(ABAddressBookRef)addressBook 
{ 
      //Run UI Updates 
      NSArray *allPeople = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook)); 
      NSInteger numberOfPeople = [allPeople count]; 

      for (NSInteger i = 0; i < numberOfPeople; i++) { 
       ABRecordRef person = (__bridge ABRecordRef)allPeople[i]; 
       //From Below code you can get what you want. 
       NSString *firstName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonFirstNameProperty)); 
       NSString *lastName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonLastNameProperty)); 
       NSLog(@"Name:%@ %@", firstName, lastName); 

       ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty); 
       NSString *phoneNumber = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phoneNumbers, 0)); 
       NSLog(@"phone:%@", phoneNumber); 
       NSLog(@"============================================="); 
      } 

}