SQL數據透視表總計

Question

在我試圖行和列總計添加到該數據透視表

 create table test4(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int) 
      insert into test4 values ('Austin', 'African-American', 'male', 21) 
      insert into test4 values ('Austin', 'Asian', 'female', 22) 
      insert into test4 values ('Austin', 'Caucasian', 'male', 23) 
      insert into test4 values ('Austin', 'Hispanic', 'female', 24) 
      insert into test4 values ('Austin', 'African-American', 'Unknown', 25) 
      insert into test4 values ('Austin', 'Asian', 'male', 26) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 27) 
      insert into test4 values ('Austin', 'Hispanic', 'Unknown', 28) 
      insert into test4 values ('Austin', 'Asian', 'male', 29) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 31) 
      insert into test4 values ('Dallas', 'Hispanic', 'Unknown', 32) 
      insert into test4 values ('Dallas', 'African-American', 'male', 33) 
      insert into test4 values ('Dallas', 'Asian', 'female', 34) 
      insert into test4 values ('Dallas', 'Caucasian', 'Unknown', 35) 
      insert into test4 values ('Dallas', 'Hispanic', 'male', 500) 
      insert into test4 values ('Dallas', 'African-American', 'female', 36) 
      insert into test4 values ('Dallas', 'Asian', 'Unknown', 37) 
      insert into test4 values ('Dallas', 'Caucasian', 'male', 38) 
      insert into test4 values ('Dallas', 'Hispanic', 'female', 39) 
      insert into test4 values ('Dallas', 'African-American', 'Unknown', 41) 
      insert into test4 values ('Houston', 'Asian', 'male', 42) 
      insert into test4 values ('Houston', 'Caucasian', 'female', 43) 
      insert into test4 values ('Houston', 'Hispanic', 'Unknown', 44) 
      insert into test4 values ('Houston', 'African-American', 'male', 45) 
      insert into test4 values ('Houston', 'Asian', 'female', 46) 
      insert into test4 values ('Houston', 'Caucasian', 'Unknown', 47) 
      insert into test4 values ('Houston', 'Hispanic', 'male', 48) 
      insert into test4 values ('Houston', 'African-American', 'female', 49) 
      insert into test4 values ('Houston', 'Asian', 'Unknown', 51) 
      insert into test4 values ('Houston', 'Caucasian', 'male', 52); 

      WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM test4 AS A 
      ) 
      SELECT * 
      FROM T 
      PIVOT(COUNT(age_range_race) FOR age_range_race 
       IN(
        [20-30_African-American], 
        [20-30_Asian], 
        [20-30_Caucasian], 
        [20-30_Hispanic], 
        [31-40_African-American], 
        [31-40_Asian], 
        [31-40_Caucasian], 
        [31-40_Hispanic], 
        [41-50_African-American], 
        [41-50_Asian], 
        [41-50_Caucasian], 
        [41-50_Hispanic] 
       ) 
      ) AS P 

我想實現這個結果

1 http://img853.imageshack.us/img853/8112/sqltotal.jpg

唯一的例子我可以在Google上找到爲SQL 2000編寫的存儲過程。請幫忙！在此先感謝

Answer 1

在這裏，你試試。

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
into #tmp_result 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P 

select * 
from #tmp_result 
union all 
select 'Grand Total','',SUM([20-30_African-American]), SUM([20-30_Asian]), SUM([20-30_Caucasian]), SUM([20-30_Hispanic]),SUM([31-40_African-American]), SUM([31-40_Asian]), SUM([31-40_Caucasian]), SUM([31-40_Hispanic]),SUM([41-50_African-American]), SUM([41-50_Asian]), SUM([41-50_Caucasian]),SUM([41-50_Hispanic]), sum(Total) 
from #tmp_result 

Answer 2

請嘗試如下..

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P