SQL - 找到行

Question

之間的值我有2個表：

• Employee表2列Name和Sales
• Rewards 2列Bonus和Range

樣品數據表：

Employee      Rewards 

| Name | Sales |    | Bonus | Range | 
+------+-------+    +-------+-------+ 
| John | 112 |    | 2  | 200 | 
| Mary | 201 |    | 3  | 300 | 
| Joe | 400 |    | 5  | 500 | 
| Jack | 300 | 

如果他的銷售< = Rewards.Range，每位員工都應該從Rewords表中獲得獎金。我想選擇Employee.Name和Rewards.Bonus。

在這種情況下，結果應該是：

| Name | Bonus | 
+------+-------+ 
| John | 2  | 
| Mary | 3  | 
| Joe | 5  | 
| Jack | 3  | 

任何想法，這個SQL查詢將是什麼？

感謝， ZB

Answer 1

我建議這種方法。可能有一個或兩個語法錯誤。

select name 
, (select bonus from rewards 
where range = 
(select min(range) 
from rewards 
where range >= sales) 
) 
from employee 

Answer 2

我會使用lag讓每個範圍的底部部分，並加入其僱員的表：

SELECT name, bonus 
FROM employee e 
JOIN (SELECT bonus, 
       range AS top_range, 
       COALESCE(LAG(range) OVER (ORDER BY bonus ASC), 0) AS bottom_range 
     FROM rewards) r ON e.sales BETWEEN r.bottom_range AND r.top_range 

Answer 3

;with OrderedBonuses as (
    select e.name, r.bonus, row_number() over (partition by e.name order by r.Range desc) as ord 
    from Employee e 
      JOIN Rewards r on e.Sales <= r.Range 
) 
select name, bonus 
from OrderedBonuses 
where ord = 1; 

Answer 4

我只是測試這一個，它取回權結果與您的測試表：

SELECT a.name, 
     MIN(b.bonus) AS bonus 
FROM db.employee a 
INNER JOIN db.rewards b 
ON a.sales <= b.range 
GROUP BY a.name;