2011-11-01 75 views
1

我有一個簡單的模型,它只是一對多關係鏈:國家 - <城市 - <街道 表格被映射爲實體並作爲地圖返回。爲什麼Hibernate HQL能夠正常工作,但Criteria沒有?

下面的試驗方法是生產奇怪的結果:

public static void main(String[] args) { 
    Session session = HibernateSessionFactory.getSession(); 

    List<Map<String, Object>> results = null; 

    //Query using HQL and print results 
    System.out.println("FROM HQL ====================="); 
    String hql = "from Street where City.Country.countryid = 1";   
    Query query = session.createQuery(hql); 
    results = query.list(); 
    for(Map<String, Object> row : results) { 
     System.out.println(row); 
    } 

    //Query using Criteria and print results 
    System.out.println("FROM CRITERIA ================"); 
    Criteria criteria = session.createCriteria("Street"); 
    criteria.add(Restrictions.eq("City.Country.countryid", 1)); 
    results = criteria.list(); 
    for(Map<String, Object> row : results) { 
     System.out.println(row); 
    } 
} 

它使用HQL的頂塊按預期方式工作,但底部塊翻倒:

輸出:

FROM HQL ===================== 
{streetname=Mayfair, [email protected], $type$=Street, streetid=1} 
{streetname=Park Lane, [email protected], $type$=Street, streetid=2} 
{streetname=Bond Street, [email protected], $type$=Street, streetid=3} 
{streetname=Old Kent Road, [email protected], $type$=Street, streetid=4} 
FROM CRITERIA ================ 
Exception in thread "main" org.hibernate.QueryException: could not resolve property: City.Country.countryid of: Street 
    at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:67) 
    at org.hibernate.persister.entity.AbstractPropertyMapping.toColumns(AbstractPropertyMapping.java:82) 
    at org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns(BasicEntityPropertyMapping.java:54) 
    at org.hibernate.persister.entity.AbstractEntityPersister.toColumns(AbstractEntityPersister.java:1367) 
    at org.hibernate.loader.criteria.CriteriaQueryTranslator.getColumns(CriteriaQueryTranslator.java:457) 
    at org.hibernate.loader.criteria.CriteriaQueryTranslator.getColumnsUsingProjection(CriteriaQueryTranslator.java:417) 
    at org.hibernate.criterion.SimpleExpression.toSqlString(SimpleExpression.java:68) 
    at org.hibernate.loader.criteria.CriteriaQueryTranslator.getWhereCondition(CriteriaQueryTranslator.java:357) 
    at org.hibernate.loader.criteria.CriteriaJoinWalker.<init>(CriteriaJoinWalker.java:113) 
    at org.hibernate.loader.criteria.CriteriaJoinWalker.<init>(CriteriaJoinWalker.java:82) 
    at org.hibernate.loader.criteria.CriteriaLoader.<init>(CriteriaLoader.java:91) 
    at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1578) 
    at org.hibernate.impl.CriteriaImpl.list(CriteriaImpl.java:306) 
    at com.bar.foo(Main.java:33) 

我看不出爲什麼HQL可以解析City.Country.countryid,但是Criteria(Restrictions)不能。

我錯過了一些明顯的東西嗎?

回答

1

因爲您對hql查詢使用了錯誤的語法。 幾個缺點:

  • Street.class而不是 「一條街」
  • 缺少別名
  • 使用國家,而不是直接country.id

試試這個:

Criteria criteria = session.createCriteria(Street.class) 
.createAlias("city", "ci") 
.add(Restrictions.eq("ci.country", country)) 

有關更多詳細信息,請參閱hibernate reference

+0

謝謝! 我不能使用Street.class,因爲我沒有Street.class。在我的應用程序中一切都是動態然而,別名的使用似乎有所幫助。 對於「路徑」的每個部分,我可以創建一個別名,如下所示: criteria.createAlias(「City」,「ci」); (限制.eq(「co.countryid」,1); 這似乎工作。 – Memran