2017-02-22 74 views
-1
var streamerStatus = []; 

var streamers = ['x', 'y', 'z']; 

for (var i = 0; i < streamers.length; i++){ 

streamerStatus.push({streamers[i]: 'OFFLINE'}); 

} 
+2

ES6:'streamerStatus.push({[拖纜[I]]: '離線'})' – Andreas

+2

ES6:'STREAMERSTATUS = streamers.map(K =>({[K]: '離線' })) – pawel

回答

0
for (var i = 0; i < streamers.length; i++){ 
    var obj = {}; 
    obj[streamers[i]] = 'OFFLINE'; 

    streamerStatus.push(obj); 
} 
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