寫入一個變量整數時，ByteBuffer.js出現意外的結果

Question

下面，我試圖寫出0x16作爲變量整數。我期待看到0x2C，但我得到0x16。任何想法如何調整我使用ByteBuffer來獲得預期結果？請按照以下意見：

http://jsfiddle.net/jslim180/h1ojuc54/

ByteBuffer = window.dcodeIO.ByteBuffer 

b = new ByteBuffer(DEFAULT_CAPACITY=4, ByteBuffer.LITTLE_ENDIAN) 

console.log '22 decimal is 0x16 hex: ' + (22).toString(16) 

# 22 can be represented in less than 7 bits so the least significant bit 
# should be 0 (indicating that no additional bytes are needed) 
b.writeVarint32 22 
b.printDebug() # Not expected: prints 0x16 .. this did not bitshift at all 

# If I bit-shift manually, I get the expected result: 0x2C 
console.log (0x16<<1).toString(16) # prints 2c 

https://github.com/dcodeIO/ByteBuffer.js/wiki/API

（順便說一句：這是CoffeeScript的，沒有括號的JavaScript）

Answer 1

字節緩衝區被寫出無符號varint。我需要使用writeVaruint32。 https://github.com/dcodeIO/ByteBuffer.js/issues/44