有沒有一個命令，以便當有些事情比事情的回答少3個或多3個時，它會做些什麼？

Question

我想提出一個隨機數字猜謎遊戲，我想知道，如果當你的猜測是不是比它會打印出類似這樣的回答少3個或更多的「關閉！答案是（答案）」

import random 
while True: 
    dicesize = raw_input('What size die do you want to guess from?>') 
    number = random.randrange(1, int(dicesize)) 
    guess = raw_input('What is your guess?>') 
    if int(guess) == number: 
     print 'Correct!' 
     print " " 
     # less than 3 print "close"? 
     # more than 3 print "close"? 
    else: 
     print 'Nope! The answer was', number 
     print " " 

（我有打印「」使每個環之間有一個空格）

Answer 1

while True: 
    dicesize = raw_input('What size die do you want to guess from?>') 
    number = random.randrange(1, int(dicesize)) 
    guess = int(raw_input('What is your guess?>')) 
    if guess == number: 
     print('Correct!') 
     print(" ") 
    elif abs(number-guess) < 3: 
     print("Close") 
    else: 
     print('Nope! The answer was', number) 

剛剛獲得absolute valueabs(number-guess)，將覆蓋這兩種情況下，如果猜測是小於3的上方或下方的號碼。

In [1]: abs(10-7) 
Out[1]: 3 

In [2]: abs(7-10) 
Out[2]: 3 

Answer 2

更簡單地說，使用鏈接條件句

if number-3 < guess < number+3: 
    print("Close")