美好的一天!我正在嘗試搜索將Android圖像文件上傳到在線MySQL數據庫的基本教程,但找不到任何內容。將Android的圖像上傳到MySQL數據庫
我現在正在開展一項活動,可以將用戶的個人資料圖片從Android上傳到在線服務器。
我需要的是像顯示一個按鈕,當它被點擊時,用戶可以從文件中選擇一個圖像。有人可以指導我這樣做嗎?提前致謝!
美好的一天!我正在嘗試搜索將Android圖像文件上傳到在線MySQL數據庫的基本教程,但找不到任何內容。將Android的圖像上傳到MySQL數據庫
我現在正在開展一項活動,可以將用戶的個人資料圖片從Android上傳到在線服務器。
我需要的是像顯示一個按鈕,當它被點擊時,用戶可以從文件中選擇一個圖像。有人可以指導我這樣做嗎?提前致謝!
在客戶端,您可以執行此操作。
HttpURLConnection connection = null;
DataOutputStream outputStream = null;
DataInputStream inputStream = null;
String pathToOurFile = "path of the image.jpeg";
String urlServer = "http://xxx.xxx.xxx.xxx/uploader.php";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
try {
FileInputStream fileInStream = new FileInputStream(new File(pathToOurFile));
URL url = new URL(urlServer);
connection = (HttpURLConnection) url.openConnection();
// Allow Inputs & Outputs
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
// Enable POST method
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
outputStream = new DataOutputStream(connection.getOutputStream());
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile +"\"" + lineEnd);
outputStream.writeBytes(lineEnd);
bytesAvailable = fileInStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file
bytesRead = fileInStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInStream.read(buffer, 0, bufferSize);
}
outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = connection.getResponseCode();
serverResponseMessage = connection.getResponseMessage();
fileInputStream.close();
outputStream.flush();
outputStream.close();
}
catch (Exception ex)
{
//Exception handling
}
服務器端
<?php
$target_path = "./";
$target_path = $target_path . basename($_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "Success";
} else{
echo "Error";
}
?>
其實我從某處找到了這段代碼,並沒有有它的鏈接所以發佈了我在我的App.Hope中使用的代碼,它可能也解決了你的問題..警告。 – 2012-07-25 06:01:54
serverResponseCode,serverResponseMessage,fileInputStream。我不知道這些變量做了什麼。我想嘗試你的代碼,但這些變量給我錯誤。 – JetPro 2012-07-25 06:06:20
將它們全部聲明爲字符串變量 – 2012-07-25 06:07:49
使用下面的代碼從ImageGallery獲取圖像:
Intent i = new Intent(Intent.ACTION_PICK,
android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(i, ACTIVITY_SELECT_IMAGE);
它將開始ImageGallery,現在你可以選擇圖像,並在onActivityResult您可以將圖像解碼爲位圖,如鏈接所示:here:
protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
super.onActivityResult(requestCode, resultCode, imageReturnedIntent);
switch(requestCode) {
case REQ_CODE_PICK_IMAGE:
if(resultCode == RESULT_OK){
Uri selectedImage = imageReturnedIntent.getData();
String[] filePathColumn = {MediaStore.Images.Media.DATA};
Cursor cursor = getContentResolver().query(selectedImage, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
String filePath = cursor.getString(columnIndex);
cursor.close();
Bitmap yourSelectedImage = BitmapFactory.decodeFile(filePath);
}
}
}
接下來,您需要將該位圖上傳到服務器。要做到這一點,你可以使用Haresh的解決方案。
試圖搜索...和你有什麼嘗試,直到現在? – Lucifer 2012-07-25 05:54:25
你可以按照這個教程,它必須幫助你 [上傳圖片](http://vikaskanani.wordpress.com/2011/01/11/android-upload-image-or-file-using-http-post -multi-part /)[圖片上傳活動](http://vikaskanani.wordpress.com/2011/01/29/android-image-upload-activity/) – Furqi 2012-07-25 05:58:48