如何通過外部引用或其他方式進行分組？

我傳遞的兩個日期，需要GROUP BY的結果通過這兩個日期，但不能這樣做，因爲我得到的錯誤如何通過外部引用或其他方式進行分組？

消息164，級別15，狀態1，行24每個GROUP BY表達式必須包含至少一個不是外部引用的列。

查詢如下：

declare @sd datetime ='2012-07-01 00:00:00.000' , 
     @ed datetime ='2012-09-30 00:00:00.000' ; 

select @sd,@ed, 
     count(i.id)as count, 
     sum(case when oi.rating <50 then 1 else 0 end) as unfav, 
     sum(case when oi.Rating =50 then 1 else 0 end) as neu, 
     sum(case when oi.Rating >50 then 1 else 0 end) as fav, 
     avg(oi.Rating)as 'Av Rating' 
     from Items i (nolock) 
     inner join ItemOrganisations oi (nolock) on i.ID= oi.ItemID 
     inner join Lookup_ItemTypes it (nolock) on it.ID = i.ItemTypeID 

     inner join Batches b (nolock) on b.ID=i.BatchID 
     inner join Lookup_ItemStatus lis (nolock) on lis.ID = i.StatusID 
     inner join Lookup_BatchStatus lbs (nolock) on lbs.ID = b.StatusID 
     inner join Lookup_BatchTypes bt on bt.id = b.Typeid 

     where lbs.Name = 'Completed by Analyst' or lbs.Name='Delivered/Imported into Neptune Online' 
     and lis.Name = 'Complete' 
     and i.IsRelevant = 1 
     and bt.Name = 'Live' 
     group by @sd,@ed 
     having i.OverrideDate between @sd and @ed

如果我這個不羣是結果我得到這是錯誤的：

2011-01-01 00:00:00.000 2011-01-31 00:00:00.000 1 0 0 1 55 
2011-01-01 00:00:00.000 2011-01-31 00:00:00.000 7 1 0 1 50 
2011-01-01 00:00:00.000 2011-01-31 00:00:00.000 7 1 0 0 20 
2011-01-01 00:00:00.000 2011-01-31 00:00:00.000 1 0 0 0 NULL 
2011-01-01 00:00:00.000 2011-01-31 00:00:00.000 8 1 0 6 66 
2011-01-01 00:00:00.000 2011-01-31 00:00:00.000 1 1 0 0 10 
2011-02-01 00:00:00.000 2011-02-28 00:00:00.000 1 0 0 1 55 
2011-02-01 00:00:00.000 2011-02-28 00:00:00.000 7 1 0 1 50 
2011-02-01 00:00:00.000 2011-02-28 00:00:00.000 7 1 0 0 20 
2011-02-01 00:00:00.000 2011-02-28 00:00:00.000 1 0 0 0 NULL 
2011-02-01 00:00:00.000 2011-02-28 00:00:00.000 8 1 0 6 66 
2011-02-01 00:00:00.000 2011-02-28 00:00:00.000 1 1 0 0 10 
2011-03-01 00:00:00.000 2011-03-31 00:00:00.000 1 0 0 1 55 
2011-03-01 00:00:00.000 2011-03-31 00:00:00.000 7 1 0 1 50 
2011-03-01 00:00:00.000 2011-03-31 00:00:00.000 7 1 0 0 20 
2011-03-01 00:00:00.000 2011-03-31 00:00:00.000 1 0 0 0 NULL 
2011-03-01 00:00:00.000 2011-03-31 00:00:00.000 8 1 0 6 66 
2011-03-01 00:00:00.000 2011-03-31 00:00:00.000 1 1 0 0 10 
2011-04-01 00:00:00.000 2011-04-30 00:00:00.000 1 0 0 1 55 
2011-04-01 00:00:00.000 2011-04-30 00:00:00.000 7 1 0 1 50 
2011-04-01 00:00:00.000 2011-04-30 00:00:00.000 7 1 0 0 20

來源

2013-02-26 Xerxes

沒有理由這樣做，請解釋一下你的結果期望與您進行分組的結果邏輯 – jazzytomato 2013-02-26 16:48:59

請參閱edit.thanks – Xerxes 2013-02-26 16:53:46

確定這些結果來自同一個查詢？你如何在前兩欄的「@ sd，@ ed」中得到不同的結果？ – Kaf 2013-02-26 17:03:53

您的查詢，如寫的，是試圖通過不斷的表達進行分組。我認爲你可以將最後兩行改爲：

and i.OverrideDate between @sd and @ed

group by聲明是不必要的。你只返回一行，所以所有的行將被聚合。

如果您需要包括group by出於某種原因（如這被自動生成的代碼），那麼你可以使用一個技巧，如：

group by (case when OverrideDate = OverrideDate then @sd end), 
     (case when OverrideDate = OverrideDate then @ed end)

，但我想這是在這個unncessary案件。

來源

2013-02-26 16:48:24

+1的情況下，當*技巧，我不知道:)（但它在這裏看起來沒用） – jazzytomato 2013-02-26 16:52:58

當使用case語句時，我仍然得到外部引用錯誤。 – Xerxes 2013-02-26 16:59:37

@xerxes。。。其實，我認爲你需要在其中有一個變量引用，現在我看看我實際使用它的代碼。 – 2013-02-26 17:08:30

我不知道爲什麼你在這裏使用group by和having條款。我認爲你可以簡化你的where子句;

where lbs.Name in ('Completed by Analyst', 
        'Delivered/Imported into Neptune Online') 
     and lis.Name = 'Complete' 
     and bt.Name = 'Live' 
     and i.IsRelevant = 1 
     and i.OverrideDate between @sd and @ed

來源

2013-02-26 16:51:48 Kaf

如何通過外部引用或其他方式進行分組？

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