如何小寫捕獲組只有斯卡拉

Question

此代碼：

"""{"nAMe": "Deloise", "WINS": [["three of a kind", "5♣"]]}""".replaceAll("""(\"[^"]+\" *:)""", "|UPERCASETEST|$1|".toLowerCase()) 

產地：

String = {|upercasetest|"nAMe":| "Deloise", |upercasetest|"WINS":| [["three of a kind", "5♣"]]} 

雖然我期待：

String = {|upercasetest|"name":| "Deloise", |upercasetest|"wins":| [["three of a kind", "5♣"]]} 

任何想法，爲什麼捕獲組不希望小寫和如何解決它？

Answer 1

你需要匹配對象傳遞給內部replaceAllIn lambda表達式，你可以操縱的內容，否則，內部replaceAll，該$1沒有得到「擴大」到實際的第1組的子匹配值：

val s = """{"nAMe": "Deloise", "WINS": [["three of a kind", "5♣"]]}""" 
val rx = """(\"[^"]+\" *:)""".r 
val replacedStr = rx replaceAllIn (s, m => s"|UPERCASETEST|${m.group(1)}|".toLowerCase()) 
println(replacedStr) 

見Scala demo

輸出：

{|upercasetest|"name":| "Deloise", |upercasetest|"wins":| [["three of a kind", "5♣"]]}