發送這是應該(在我的PHP代碼)發送郵件:郵件無法通過形式
$message =
"Hello \n
Thank you for registering with us. Here are your login details...\n
User ID: $user_name
Email: $usr_email \n
Passwd: $data[pwd] \n
";
mail($usr_email, "Login Details", $message,
"From: \"Member Registration\" <[email protected]>\r\n" .
"X-Mailer: PHP/" . phpversion());
header("Location: thankyou.php");
exit();
這是我的php.ini細節:
; For Win32 only.
; http://php.net/smtp
;SMTP = localhost
; http://php.net/smtp-port
;smtp_port = 25
; For Win32 only.
; http://php.net/sendmail-from
;sendmail_from = [email protected]
; For Unix only. You may supply arguments as well (default: "sendmail -t -i").
; http://php.net/sendmail-path
sendmail_path = "\"C:\xampp\sendmail\sendmail.exe\" -t"
; Force the addition of the specified parameters to be passed as extra parameters
; to the sendmail binary. These parameters will always replace the value of
;the 5th parameter to mail(), even in safe mode.
;mail.force_extra_parameters =
; Add X-PHP-Originating-Script: that will include uid of the script followed by the
;filename
mail.add_x_header = Off
; Log all mail() calls including the full path of the script, line #, to address and
;headers
;mail.log = "C:\xampp\apache\logs\php_mail.log"
和我sendmail.ini
[sendmail]
smtp_server=smtp.gmail.com
smtp_port=25
error_logfile=error.log
debug_logfile=debug.log
[email protected]
auth_password=xxxxxxx
[email protected]
我是一個完整的初學者,所以這可能是完全錯誤的。 當我提交郵件功能的表單時,會顯示thankyou.php頁面
你試過用var_dump()函數來查看出現了什麼錯誤?如果不嘗試將你的郵件函數放入'var_dump(mail(...));' – orustam 2012-04-01 22:22:16