JavaScript的 - 比較2個陣列與空間

Question

分裂我有2列：

sentence [] 
keywords [] 

例如sentence []：

sentence [0] = "my car is blue" 
sentence [1] = "the dog is sleeping" 
sentence [2] = "I am in the kitchen" 
sentence [3] = "How are you" 

和keywords []：

keywords [0] = "my" 
keywords [1] = " " 
keywords [2] = "car" 
keywords [3] = " " 
keywords [4] = "is" 
keywords [5] = " " 
keywords [6] = "blue" 
keywords [7] = "gghcxfkjc" 
keywords [8] = "532jj" 
keywords [9] = "How" 
keywords [10] = " " 
keywords [11] = "are" 
keywords [12] = " " 
keywords [13] = "you" 
keywords [14] = " " 
keywords [15] = "tech" 

因此，舉例來說，我需要檢測到「我的車是藍色的」和「 你好嗎「在keywords陣列。 請注意，關鍵字[]遵循句子的順序。

如何才能繼續比較和檢測這種信息？

[編輯]我需要知道的關鍵字匹配每個詞的索引[] 例如0,1,2,3,4的第一句話9,10,11,12,13爲另一句話。

Answer 1

所以，你想通過sentence循環，並檢查是否有任何句子在關鍵字中。

這將這樣的伎倆：

// Build a big string of all keywords 
var keyWordLine = keywords.join('').toLowerCase(); // "my car is bluegghcxfkjc532jjHow are you tech" 
// Loop through all sentences 
for(var i = 0; i < sentence; i++){ 
    // Check the current sentence 
    if(keyWordLine.indexOf(sentence[i].toLowerCase()) !== -1){ 
     // sentence is in the keywords! 
    }else{ 
     // sentence is not in the keywords! 
    } 
} 

現在，您將與這些結果做什麼是由你。你可以，例如，建立一個包括只出現在keywords句子的數組：

var keywords = ["my", " ", "car", " ", "is", " ", "blue", "gghcxfkjc", "532jj", "How", " ", "are", " ", "you", " ", "tech"], 
 
    sentence = ["my car is blue", "the dog is sleeping", "I am in the kitchen", "How are you"], 
 
    keyWordLine = keywords.join('').toLowerCase(), 
 
    output = []; 
 
for(var i = 0; i < sentence; i++){ 
 
    if(keyWordLine.indexOf(sentence[i].toLowerCase()) !== -1){ 
 
     output.push(sentence[i]); 
 
    } 
 
} 
 
alert(output);

Answer 2

只是join的關鍵字，並期待這句話得到的字符串中：

kw = keywords.join("") 
sentence.forEach(function(s) { 
    console.log(s, kw.indexOf(s) >= 0); 
}); 

打印

my car is blue true 
the dog is sleeping false 
I am in the kitchen false 
How are you true