1
我有一個包含「用戶會話」的表,另一個表包含系統中的違規行爲。一種可能的違規行爲是讓用戶直接登錄超過12小時。使用另一個表中的數據過濾MySQL表
中的表如下:
notification:
+--------------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+-------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| host_id | int(11) | NO | MUL | NULL | |
| alert_id | int(11) | NO | MUL | NULL | |
| event_start | datetime | NO | | NULL | |
| time_noticed | datetime | NO | | NULL | |
| info | varchar(45) | YES | | NULL | |
| seen | int(11) | NO | | NULL | |
+--------------+-------------+------+-----+---------+----------------+
login:
+----------+-------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------+-------------+------+-----+---------+-------+
| username | varchar(45) | NO | | NULL | |
| host_id | int(11) | NO | MUL | NULL | |
| start | datetime | NO | | NULL | |
| end | datetime | NO | | NULL | |
| last | int(11) | NO | | NULL | |
+----------+-------------+------+-----+---------+-------+
我想要的結果表中的條件是:
login.last = 1,login.host_id = X,端>啓動+12小時
並請確保我之前沒有報告過此實例:
login.host_id!= notification.host_id,notification.alert_id!= Y,login.start!= notification.event_start,login.username!= notification.info
(in換句話說,我不想在同一臺主機上得到同一用戶的另一份報告,從而使得這個報告成爲可能它開始在同一時間同一違法行爲)
你已經嘗試過了什麼,沒有奏效? – 2012-03-19 15:33:28
SELECT username,start FROM login LEFT OUTER JOIN notification ON(login.host_id!= notification.host_id OR alert_id!= $ alert_id OR start!= event_start or username!= info)WHERE end> DATE_ADD(start,INTERVAL 12 HOUR)AND login.host_id = $ host_id AND last = 1 – hizki 2012-03-19 15:39:15