2017-02-26 75 views
0

我想僅通過標識獲取用戶deleted=0。我試過過濾一個查詢,然後通過使用SQLAlchemy標識獲得一行

user = User.query.filter_by(deleted=0).get(id) 

但是出錯了。如何過濾查詢並通過ID獲取?

Traceback (most recent call last): 
    File "<stdin>", line 1, in <module> 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 831, in get 
    return self._get_impl(ident, loading.load_on_ident) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 864, in _get_impl 
    return fallback_fn(self, key) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/loading.py", line 177, in load_on_ident 
    q._get_condition() 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 350, in _get_condition 
    "get", order_by=False, distinct=False) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 368, in _no_criterion_condition 
    self._no_criterion_assertion(meth, order_by, distinct) 
    File "/home/david/.virtualenvs/flask-sqlalchemy/lib/python3.6/site-packages/sqlalchemy/orm/query.py", line 365, in _no_criterion_assertion 
    "Query with existing criterion. " % meth) 
sqlalchemy.exc.InvalidRequestError: Query.get() being called on a Query with existing criterion. 

回答

2

由於錯誤提示,get僅適用於未篩選查詢的情況。如果你想過濾,也可以用id進行過濾,並使用first

user = User.query.filter_by(id=id, deleted=0).first()