提交按鈕不會設置

Question

我們無法獲取刪除「提交」按鈕進行設置，否則會起作用，我們無法理解哪部分代碼是錯誤的。

想象有幾列，其中從數據庫中包含數據的TD的

// While it goes through each row (which is selected from another SQL query above, but I won't bother pasting that) 
while ($row = mysql_fetch_array($result)) { 
// Variable is equal to the Request ID (e.g. 10) 
$numb = $row['ReqID']; 

// Echo's the table td rows with each column name in the database 
echo "<tr>"; 
echo "<td class='req' align='center'>".$row['ReqID']."</td>"; 
echo "<td class='req' align='center'>".$row['ModTitle']."</td>"; 
echo "<td class='req' align='center'>".$row['BuildingID']."</td>"; 
echo "<td class='req' align='center'>".$row['RoomID']."</td>"; 
echo "<td class='req' align='center'>".$row['Priority']."</td>"; 
echo "<td class='req' align='center'>".$row['W1']."</td>"; 
echo "<td class='req' align='center'>".$row['P1']."</td>"; 
// Delete button also in a td row, uses the variable "$numb" to set the button name 
echo "<td class='req' align='center'><input type='submit' name='{$numb}' value='Delete'></td>"; 
echo "</tr>"; 

// If the delete button is pressed, delete the row (this query works, we tested it, but the button just doesn't set so it doesn't activate the SQL command) 
if (isset($_POST[$numb])) { 
$result2 = mysql_query("DELETE FROM Request WHERE ReqID = {$numb} LIMIT 1", $connection); 
} 
} 

Answer 1

使用hidden輸入存儲值錶行：

以上地方......

<form method="post" action="delete.php"> 

稍微低於...

echo "<td class='req' align='center'><input type='submit' name='submit' value='Delete'>"; 
echo '<input name="hello" type="hidden" value="$numb" /></td>'; 
... 
$number = mysql_real_escape_string($_POST["hello"]); 
$result2 = mysql_query("DELETE FROM Request WHERE ReqID = ".$number." LIMIT 1", $connection); 

底部：

</form> 

注：

你的做法是不夠安全的。我可以輕鬆地編輯DOM併爲隱藏字段（或按鈕的另一個名稱）提供另一個值，從而刪除數據庫中的其他元素。請記住這一點。