3
我想要兩個哈希表以下的XML。第一個是(屏幕ID,小工具ID) 和第二個是(小工具ID,字符串ID)。如何使用DOM解析此XML並將其內容放入散列表中?
我已經能夠使用DOM解析此XML,但將其內容放入哈希表是我沒有做的。
<?xml version="1.0" encoding="UTF-8"?>
<screen id="616699" name ="SCR_NEW_HOME">
<widget id="617259" type="label" name= "NEW_HOME_TITLE">
<attribute type = "Strings">
<val id="54">HOME_SYSSETUP</val>
</attribute>
</widget>
<widget id="616836" type = "label" name ="HOME_MENU">
<attribute type="Strings">
<val id="1815" >DAILY</val>
<val id="2060" >MONTH_NOV</val>
<val id="1221" >ASPECT_RATIO_PANSCAN</val>
</attribute>
</widget>
<screen id="1556" name="SCR_EVENTLIST">
<widget id="77009" type= "label" name="EL_GUIDE_EVENT_TABLE">
<attribute type ="Strings">
<val id="1">time</val>
<val id="2">date</val>
</attribute>
</widget>
<widget id="186461" type= "label" name= "EL_PIG_CONT">
<attribute type ="Strings">
<val id="3">progress bar</val>
<val id="4">video</val>
</attribute>
</widget>
,我已經嘗試的代碼是
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import org.xml.sax.SAXException;
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Hashtable;
public class ReadXmlFile {
private static Hashtable<Integer,ArrayList<Integer>> D1 = new Hashtable<Integer, ArrayList<Integer>>();
private static Hashtable<Integer,ArrayList<Integer>> D2 = new Hashtable<Integer,ArrayList<Integer>>();
static Integer ScreenID;
static ArrayList<Integer> StringID;
static ArrayList<Integer> WidgetID;
static Integer WidgetID2;
public static void main(String argv[]) {
// try {
File fXmlFile = new File("E:/eclipse workspace/stringValidation/screens.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = null;
try {
dBuilder = dbFactory.newDocumentBuilder();
} catch (ParserConfigurationException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
Document doc = null;
try {
doc = dBuilder.parse(fXmlFile);
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
if(doc.hasChildNodes()){
printNote(doc.getChildNodes());
}
}
private static void printNote(NodeList nodeList) {
for (int count = 0; count < nodeList.getLength(); count++) {
Node tempNode = nodeList.item(count);
// make sure it's element node.
if (tempNode.getNodeType() == Node.ELEMENT_NODE) {
// get node name and value
System.out.println("\nNode Name =" + tempNode.getNodeName() + " [OPEN]");
System.out.println("Node Value =" + tempNode.getTextContent());
if (tempNode.hasAttributes()) {
// get attributes names and values
NamedNodeMap nodeMap = tempNode.getAttributes();
for (int i = 0; i < nodeMap.getLength(); i++) {
Node node = nodeMap.item(i);
System.out.println("attr name : " + node.getNodeName());
System.out.println("attr value : " + node.getNodeValue());
}
}
if (tempNode.hasChildNodes()) {
// loop again if has child nodes
printNote(tempNode.getChildNodes());
}
System.out.println("Node Name =" + tempNode.getNodeName() + " [CLOSE]");
}
}
}
}
請你能發佈所有相關代碼的問題嗎?大多數用戶可能不想或有時間編寫一個DOM解析器,以便解決「放入哈希表」的實際問題。 – andyb 2013-03-14 09:14:16
[你有什麼嘗試?](http://mattgemmell.com/2008/12/08/what-have-you-tried/) – dokaspar 2013-03-14 09:16:19
我已經把這裏,無論我試過@andyb – Shalini 2013-03-21 14:27:19