2017-11-11 57 views

回答

0

可以wrtie:

$result=mysqli_query($conn,$sql);

代碼示例:

<?php 
$servername = "localhost"; 
$username = "username"; 
$password = "password"; 
$dbname = "myDB"; 

// Create connection 
$conn = mysqli_connect($servername, $username, $password, $dbname); 
// Check connection 
if (!$conn) { 
    die("Connection failed: " . mysqli_connect_error()); 
} 

$sql = "SELECT id, firstname, lastname FROM MyGuests"; 
$result = mysqli_query($conn, $sql); 

if (mysqli_num_rows($result) > 0) { 
    // output data of each row 
    while($row = mysqli_fetch_assoc($result)) { 
     echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>"; 
    } 
} else { 
    echo "0 results"; 
} 

mysqli_close($conn); 
?> 
+0

我不想選擇,但需要按照gr_id的順序連續nos。如果只是更新查詢觸發它正確執行,但對於常量@a它會給出錯誤 –