2017-07-13 30 views
1

我有這三個查詢和第一個和第二個查詢正確運行,然後我使用這些查詢來形成第三個查詢。意外的令牌:SELECT在第1行第485列

String CHECK_FOR_COMBOS1 = " SELECT new com.xxxx.domain.OpenCombo(productSub.id , CASE WHEN productClass.productClassIsProduction = 1 " 
     + "THEN 0 ELSE 1 END) FROM ProductSub productSub, Product product, ProductGroup productGroup," 
     + "ProductClass productClass " 
     + " WHERE productSub.id = :productSubId" 
     + " AND product.id = productSub.productId" 
     + " AND productGroup.id = product.productGroupId" 
     + " AND productClass.id = productGroup.productClassId"; 

String CHECK_FOR_COMBOS2 = "SELECT 1 FROM ProductSubProductSub productSubProductSub ,ProductSub productSub, Product product," 
     + "ProductGroup productGroup,ProductClass productClass " 
     + " WHERE productSub.id = productSubProductSub.childProductSubId " 
     + " AND product.id = productSub.productId " 
     + " AND productGroup.id = product.productGroupId " 
     + " AND productClass.id = productGroup.productClassId AND productClass.productClassIsProduction = 0" 
     + " AND productSubProductSub.productSubId = :productSubId "; 

String CHECK_FOR_COMBOS3 = CHECK_FOR_COMBOS1 + " AND (EXISTS " +CHECK_FOR_COMBOS2 + ") GROUP BY productSub.id , " 
     + " productClass.productClassIsProduction " ; 

當我運行第三個查詢時,出現以下錯誤。

Caused by: java.lang.IllegalArgumentException: Validation failed for query for method public abstract com.xxxx.domain.OpenCombo com.xxxx.repository.ProductSubRepository.findItemHasCombo(int)! 
    at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:97) 
    at org.springframework.data.jpa.repository.query.SimpleJpaQuery.<init>(SimpleJpaQuery.java:66) 
    at org.springframework.data.jpa.repository.query.SimpleJpaQuery.fromQueryAnnotation(SimpleJpaQuery.java:169) 
    at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$DeclaredQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:114) 
    at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateIfNotFoundQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:160) 
    at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$AbstractQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:68) 
    at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.<init>(RepositoryFactorySupport.java:304) 
    at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:161) 
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject(RepositoryFactoryBeanSupport.java:162) 
    at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.getObject(RepositoryFactoryBeanSupport.java:44) 
    at org.springframework.beans.factory.support.FactoryBeanRegistrySupport.doGetObjectFromFactoryBean(FactoryBeanRegistrySupport.java:168) 
    ... 90 more 
Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: SELECT near line 1, column 485 [ SELECT new com.xxxx.domain.OpenCombo(productSub.id , CASE WHEN productClass.productClassIsProduction = 1 THEN 0 ELSE 1 END) FROM com.xxxx.domain.ProductSub productSub, com.xxxx.domain.Product product, com.xxxx.domain.ProductGroup productGroup,com.xxxx.domain.ProductClass productClass WHERE productSub.id = :productSubId AND product.id = productSub.productId AND productGroup.id = product.productGroupId AND productClass.id = productGroup.productClassId AND (EXISTS SELECT 1 FROM com.xxxx.domain.ProductSubProductSub productSubProductSub ,com.xxxx.domain.ProductSub productSub, com.xxxx.domain.Product product,com.xxxx.domain.ProductGroup productGroup,com.xxxx.domain.ProductClass productClass WHERE productSub.id = productSubProductSub.childProductSubId AND product.id = productSub.productId AND productGroup.id = product.productGroupId AND productClass.id = productGroup.productClassId AND productClass.productClassIsProduction = 0 AND productSubProductSub.productSubId = :productSubId ) GROUP BY productSub.id , productClass.productClassIsProduction ] 
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750) 
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677) 
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683) 
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:331) 
    at sun.reflect.GeneratedMethodAccessor68.invoke(Unknown Source) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
    at java.lang.reflect.Method.invoke(Method.java:498) 
    at org.springframework.orm.jpa.ExtendedEntityManagerCreator$ExtendedEntityManagerInvocationHandler.invoke(ExtendedEntityManagerCreator.java:342) 
    at com.sun.proxy.$Proxy74.createQuery(Unknown Source) 
    at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:91) 
    ... 100 more 
Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: SELECT near line 1, column 485 [ SELECT new com.xxxx.domain.OpenCombo(productSub.id , CASE WHEN productClass.productClassIsProduction = 1 THEN 0 ELSE 1 END) FROM com.xxxx.domain.ProductSub productSub, com.xxxx.domain.Product product, com.xxxx.domain.ProductGroup productGroup,com.xxxx.domain.ProductClass productClass WHERE productSub.id = :productSubId AND product.id = productSub.productId AND productGroup.id = product.productGroupId AND productClass.id = productGroup.productClassId AND (EXISTS SELECT 1 FROM com.xxxx.domain.ProductSubProductSub productSubProductSub ,com.xxxx.domain.ProductSub productSub, com.xxxx.domain.Product product,com.xxxx.domain.ProductGroup productGroup,com.xxxx.domain.ProductClass productClass WHERE productSub.id = productSubProductSub.childProductSubId AND product.id = productSub.productId AND productGroup.id = product.productGroupId AND productClass.id = productGroup.productClassId AND productClass.productClassIsProduction = 0 AND productSubProductSub.productSubId = :productSubId ) GROUP BY productSub.id , productClass.productClassIsProduction ] 
    at org.hibernate.hql.internal.ast.QuerySyntaxException.convert(QuerySyntaxException.java:91) 
    at org.hibernate.hql.internal.ast.ErrorCounter.throwQueryException(ErrorCounter.java:109) 
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.parse(QueryTranslatorImpl.java:304) 
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:203) 
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158) 
    at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:126) 
    at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:88) 
    at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:167) 
    at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301) 
    at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236) 
    at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800) 
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:328) 
    ... 106 more 

它抱怨後EXISTS關鍵字,我注意到這是在Hibernate中也是如此。任何人都可以給我一個提示來解決這個問題嗎?有沒有比編寫上述查詢更好的處理方法?

回答

1

首先,你錯過了()爲存在clausule。另外,我不太確定您可以在AND條件中使用EXISTS子句。如果這在SQL上有效,你可以試試這個:

String CHECK_FOR_COMBOS3 = CHECK_FOR_COMBOS1 + " AND (EXISTS (" +CHECK_FOR_COMBOS2 + ")) GROUP BY productSub.id , " 
    + " productClass.productClassIsProduction " ; 
+0

謝謝,我在沒有這個幫助的情況下找到了。 – newday

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