我有一個程序可以創建XML日誌。首先,我檢查,如果XML存在,如果不是我用下面的代碼來創建它:將新行添加到XML文件
XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;
using (XmlWriter writer = XmlWriter.Create(myXMLLog, settings))
{
writer.WriteStartDocument();
writer.WriteComment("Comment here.");
writer.WriteStartElement("Batch");
writer.WriteAttributeString("ID", BatchID);
writer.WriteAttributeString("Date", now);
writer.WriteStartElement("Step");
writer.WriteElementString("Name", step);
writer.WriteElementString("Success", success);
writer.WriteElementString("Message", message);
writer.WriteStartElement("Transaction");
writer.WriteElementString("ID", transID);
writer.WriteElementString("Details", details);
writer.WriteEndElement();
writer.WriteEndDocument();
}
可正常工作,並創建文件:
<!--This log was created by the Application.-->
<Batch Date="1/22/2014 10:01:11 PM" ID="166bf0d2-3bd4-4353-b309-20b6d0d59a93">
<Step>
<Name>Start Batch</Name>
<Success>1</Success>
<Message>Processing Batch</Message>
<Transaction>
<ID>N/A</ID>
<Details>N/A</Details>
</Transaction>
</Step>
所以第二次檢查XML是否存在,它確實存在,所以不要創建它,而應該添加它。我使用下面的代碼是:
XDocument xmlDoc = XDocument.Load(myXMLLog);
XElement root = new XElement("Batch");
root.Add(new XAttribute("ID", BatchID));
root.Add(new XAttribute("Date", now));
root.Add(new XElement("Step"));
root.Add(new XAttribute("Name", step));
root.Add(new XAttribute("Success", success));
root.Add(new XAttribute("Message", message));
root.Add(new XElement("Transaction"));
root.Add(new XAttribute("ID", transID));
root.Add(new XAttribute("Details", details));
xmlDoc.Element("Batch").Add(root);
xmlDoc.Save(myXMLLog);
所以現在我期待的XML文件看起來像這樣:
<!--This log was created by the Application.-->
<Batch Date="1/22/2014 10:01:11 PM" ID="166bf0d2-3bd4-4353-b309-20b6d0d59a93">
<Step>
<Name>Start Batch</Name>
<Success>1</Success>
<Message>Processing Batch</Message>
<Transaction>
<ID>N/A</ID>
<Details>N/A</Details>
</Transaction>
</Step>
</Batch>
<Batch Date="1/22/2014 10:20:00 PM" ID="166bf0d2-3bd4-4353-b309-20b6d0d5aaa">
<Step>
<Name>Start Batch</Name>
<Success>1</Success>
<Message>Processing Batch</Message>
<Transaction>
<ID>N/A</ID>
<Details>N/A</Details>
</Transaction>
</Step>
</Batch>
而是我得到一個異常「的重複屬性」。
我在做什麼錯?
謝謝!
編輯:
XML文檔確實有在它的頂部。有效的XML會非常好,但不是最重要的。
編輯編輯:
這是我的代碼現在的樣子:現在
if (File.Exists(myXMLLog))
{
XDocument xmlDoc = XDocument.Load(myXMLLog);
XElement root = new XElement("Batch",
new XAttribute("ID", BatchID),
new XAttribute("Date", now),
new XElement("Step",
new XElement("Name", step),
new XElement("Success", success),
new XElement("Message", message),
new XElement("Transaction",
new XAttribute("IDTrans", transID),
new XAttribute("Details", details))));
xmlDoc.Root.Add(root);
xmlDoc.Save(myXMLLog);
}
else
{
using (XmlWriter writer = XmlWriter.Create(myXMLLog, settings))
{
writer.WriteStartDocument();
writer.WriteComment("This log was created by the Application.");
writer.WriteStartElement("Batch");
writer.WriteAttributeString("ID", BatchID);
writer.WriteAttributeString("Date", now);
writer.WriteStartElement("Step");
writer.WriteElementString("Name", step);
writer.WriteElementString("Success", success);
writer.WriteElementString("Message", message);
writer.WriteStartElement("Transaction");
writer.WriteElementString("IDTrans", transID);
writer.WriteElementString("Details", details);
writer.WriteEndElement();
writer.WriteEndDocument();
}
}
我確定與XML的格式,我的問題是,在做內部的批首批
<Batch Date="1/22/2014 11:49:17 PM" ID="6966578b-b326-4f16-a315-1b4228a9fa42">
<Step><Name>Create DataTable</Name>
<Success>1</Success>
<Message>DataTable was Created and Populated</Message>
<Transaction>
<IDTrans>N/A</IDTrans>
<Details>0</Details>
</Transaction>
</Step>
<Batch Date="1/22/2014 11:49:17 PM" ID="6966578b-b326-4f16-a315-1b4228a9fa42">
<Step>
<Name>Send Email</Name>
<Success>1</Success>
<Message>Template Seleted and Filled</Message>
<Transaction Details="Email To: [email protected] Link: " IDTrans="243b0a3c-d8b7-49c3-b1d0-asdfsdsdfsdf"/>
</Step>
</Batch>.....
編輯FINAL
工作守則,所有的答案的組合:
if (File.Exists(myXMLLog))
{
XDocument xmlDoc = XDocument.Load(myXMLLog);
XElement root = new XElement("Batch",
new XAttribute("ID", BatchID),
new XAttribute("Date", now),
new XElement("Step",
new XElement("Name", step),
new XElement("Success", success),
new XElement("Message", message),
new XElement("Transaction",
new XAttribute("IDTrans", transID),
new XAttribute("Details", details))));
xmlDoc.Root.Add(root);
xmlDoc.Save(myXMLLog);
}
else
{
using (XmlWriter writer = XmlWriter.Create(myXMLLog, settings))
{
writer.WriteStartDocument();
writer.WriteComment("This log was created by the Application.");
writer.WriteStartElement("Root");
writer.WriteStartElement("Batch");
writer.WriteAttributeString("ID", BatchID);
writer.WriteAttributeString("Date", now);
writer.WriteStartElement("Step");
writer.WriteElementString("Name", step);
writer.WriteElementString("Success", success);
writer.WriteElementString("Message", message);
writer.WriteStartElement("Transaction");
writer.WriteElementString("IDTrans", transID);
writer.WriteElementString("Details", details);
writer.WriteEndElement();
writer.Flush();
writer.WriteEndDocument();
}
}
我很滿意的結果。如果任何人有關於如何更好地格式化XML的建議,請這樣做。感謝大家。
旁註:你想製造出任何不XML,它是XML片段的集合(因爲它缺乏袋鼠t節點)。它不能用默認的XML閱讀器讀取,但如果需要的話,你可以配置.Net'XmlReader'來期望「XML片段」而不是文檔。一些記錄器使用的類似附件友好的XML片段格式... –
考慮更新您的問題,無論您想要的是有效的XML還是您當前詢問的格式。 –