我的Swift 3代碼有一個基金會Data字節集合(從SQlite BLOB讀取)。數據的內部內容具有以下結構的多個塊:Swift 3如何解析數據
{
UINT32 count; // number of points in this trkseg
UINT32 colour; // RGB colour of the line drawn for this trkseq
Double lat; // latitude of 1st point
Double long; // longitude of 1st point
Coord point[count-1] // array of points (2nd to last points)
}
typedef struct {
Float lat // difference in latitude of this point from the lat of the 1st point
Float long // difference in longitude of this point from the lat of the 1st point
} Coord;
這很容易在C和Java中解析。不幸的是,我不能找出用Swift 3解析這個問題的最佳方法。我不是問如何解析這個確切的數據佈局,而僅僅是爲了解析Swift 3中的這些原始數據的建議和最佳實踐。從網絡搜索和Apple文檔我很遺憾!
***答案 - 感謝Martin R讓我走上正軌。我在這裏添加一些代碼來展示我如何解決這個問題,以防止它幫助其他人。正如馬丁所說,有很多方法可以解決這個問題。我的解決方案可以確保無論主機字節順序如何,blob數據都將正確解析,而網絡endian順序(大端)將始終正確解析。
/// Parse the SQLite data blob to add GPS track segments
///
/// - Parameter data: GPS track information
private func addTracks(_ data: Data) {
// The data holds compressed GPX data. It has multiple track segments.
// It has a block of binary data per track segment with this structure:
// {
// UINT32 count; // number of points in this trkseg
// UINT32 colour; // RGB colour of the line drawn for this trkseq
// Double lat; // latitude of 1st point
// Double long; // longitude of 1st point
// Coord point[count-1] // array of points (2nd to last points)
// }
//
// typedef struct {
// Float lat // difference in latitude of this point from the lat of the 1st point
// Float long // difference in longitude of this point from the lat of the 1st point
// } Coord;
var dataCount = data.count // number of data bytes
var pointCount = 0 // counts coordinates per trkseg
var colour:UInt = 0
var lat:Double = 0.0
var long:Double = 0.0
var bigEndian = true
var i = 0
// From http://codereview.stackexchange.com/questions/114730/type-to-byte-array-conversion-in-swift
if (NSHostByteOrder() == NS_LittleEndian) {
bigEndian = false
}
while (dataCount >= 40) {
pointCount = Int(self.uint32Value(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
if (pointCount < 2 || ((pointCount-1)*8 + 24 > dataCount)) {
print("ERROR, pointCount=\(pointCount)")
break
}
colour = UInt(self.uint32Value(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
let firstLat = self.doubleValue(data: data.subdata(in: i..<i+8), isBigEndian: bigEndian)
i = i+8
let firstLong = self.doubleValue(data: data.subdata(in: i..<i+8), isBigEndian: bigEndian)
i = i+8
print("pointCount=\(pointCount) colour=\(colour) firstLat=\(firstLat) firstLong=\(firstLong)")
for _ in 1..<pointCount {
lat = firstLat - Double(self.floatValue(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
long = firstLong - Double(self.floatValue(data: data.subdata(in: i..<i+4), isBigEndian: bigEndian))
i = i+4
print("lat=\(lat) long=\(long)")
}
dataCount = dataCount - 24 - (pointCount-1)*8;
}
}
private func floatValue(data: Data, isBigEndian: Bool) -> Float {
if (isBigEndian) {
return Float(bitPattern: UInt32(littleEndian: data.withUnsafeBytes { $0.pointee }))
}
else {
return Float(bitPattern: UInt32(bigEndian: data.withUnsafeBytes { $0.pointee }))
}
}
private func doubleValue(data: Data, isBigEndian: Bool) -> Double {
if (isBigEndian) {
return Double(bitPattern: UInt64(littleEndian: data.withUnsafeBytes { $0.pointee }))
}
else {
return Double(bitPattern: UInt64(bigEndian: data.withUnsafeBytes { $0.pointee }))
}
}
private func uint32Value(data: Data, isBigEndian: Bool) -> UInt32 {
if (isBigEndian) {
return data.withUnsafeBytes{ $0.pointee }
}
else {
let temp: UInt32 = data.withUnsafeBytes{ $0.pointee }
return temp.bigEndian
}
}
非常有幫助的回答。數據以網絡端序(big endian)存儲,因此需要轉換爲小端。我可以使用「let color = rawPointer.load(fromByteOffset:0,as:UInt32.self).bigEndian」將Uint32值轉換爲little endian。這種轉換不適用於Double。 http://stackoverflow.com/questions/41161034/how-to-convert-bytes-to-a-float-value-in-swift描述了一種處理轉換的方法。這是最簡單的嗎?我不禁認爲這太複雜了,必須有一個更簡單的方法。 – pbm
@pbm:你可以先將它讀入UInt64(帶有endian轉換),然後用'Double(bitPattern:...)'將它分配給Double。 - 你如何在C或Java中做到這一點? –