訪問內部paginator部分的請求參數

Question

• 1）我如何訪問搜索$keyword裏面的paginator部分創建搜索freindly網址？顯然，傳遞關鍵字$ this-> view-> paginator->關鍵字不起作用。

• 2）目前，搜索按鈕的名稱也作爲參數發送。例如，當搜索「a」時，url變成http://localhost/search/index/search/a/submit//page/2。任何方式來阻止這一點？

搜索表單：

---

<form id="search" method="get" action="/search"> 
         <input id="searchfield" onClick="this.value=''" type="text" name="search" value="Search wallpapers"/> 
         <input id="searchbutton" type="submit" value="" name="submit"/> 
        </form> 

---

行動中searchController：

---

public function indexAction() 
    {   
     $keyword=$this->_request->getParam('search');   
     $alnumFilter=new Zend_Filter_Alnum(); 
     $dataModel=new Model_data();   

     $adapter=$dataModel->fetchPaginatorAdapter("title LIKE '%".$keyword."%'", ''); 
     $paginator=new Zend_Paginator($adapter); 
     $paginator->setItemCountPerPage(18); 
     $page=$this->_request->getParam('page', 1); 
     $paginator->setCurrentPageNumber($page); 

     $this->view->paginator=$paginator; 
     $this->view->keyword=$keyword; 

    } 

index.phtml（圖）文件：

---

partialLoop（ '壁紙/表row.phtml'，$這個 - >分頁程序）;>

<div id="page-links"> 

     <?= $this->paginationControl($this->paginator,'Sliding','partials/search-pagination-control.phtml');?>  

    </div> 

搜索分頁程序-control.phtml文件：

---

if ($this->pageCount){ 
    $params=Zend_Controller_Front::getInstance()->getRequest()->getParams(); 


    if(isset($this->previous)){ 
    ?> 
     <a href="<?php echo $this->url(array_merge($params,array('page'=>$this->previous)));?>">Previous</a> 
    <?php 
    } 
    else{ 
     ?> Previous <?php 
    } 

    foreach($this->pagesInRange as $page){ 
     if($page !=$this->current){ 
      ?> 
     <a href="<?echo $this->url(array_merge($params,array('page'=>$page)));?>"><?=$page;?></a> 
     <? 
     } 
     else{ 
      echo $page; 
     } 
    } 

    if(isset($this->next)){ 
    ?> 
     <a href="<?php echo $this->url(array_merge($params,array('page'=>$this->next)));?>">Next</a> 
    <?php 
    } 
    else{ 
     ?> Next <?php 
    } 
} 

Answer 1

的paginationControl視圖助手接受一個第四參數，第在是一個參數數組，所以你的情況，你可以做這樣的事情：

<div id="page-links"> 

    <?= $this->paginationControl($this->paginator,'Sliding','partials/search-pagination-control.phtml', array('keyword' => $this->keyword));?>  

</div> 

然後你訪問你的分頁使用$這 - >關鍵字裏面。