我一直在努力解決這個問題幾天了,我似乎不能提出解決方案,我也不能看到我的錯在哪裏。PHP PDO - dblib MSSQL - SQL連接問題
我試圖寫一個查詢在sql中有一對夫婦連接,因爲我需要顯示在幾個不同的表中找到的信息。
我的問題在於連接,每當我做連最簡單的連接時,我的查詢都不會返回任何內容。以下是2個嘗試過的例子。希望我只是在語法中丟失了一些東西。從dbo.VehicleJobHistory
dbo.VehicleJobHistory:
VehicleID Number
BookingID Text
DriverID Number
PickupSuburb Text
DestinationSuburb Text
ReasonDispatched Text
TimeJobRequired Date/Time
TimeCarAccepted Date/Time
TimeCarPickup Date/Time
TimeCarComplete Date/Time
KmToPickup Number
KmOfJob Number
_timestamp DateTime
樣品日期:
$ STH = $ DBH->查詢(「SELECT * FROM dbo.VehicleJobHistory WHERE TimeJobRequired> 」2013年2月3日「 AND VehicleID = 」451「 「);
三千零十六萬二千零九十分之四百五十一/ 8387/Springwood的/ Springwood的// 02月03日2013 12:58:23:800AM /// 0/0/451 /八千三百八十七分之三千〇一十六萬三千〇七十一/ Loganholme/Loganholme // 02月03日2013 01:23:45:263AM /// 1200/4250/451/30163856/8387/Shailer Park/Shailer Park // 2013年2月3日01:45:50:450AM /// 0/0/0 451/30163965/8387/Loganholme/Runcorn // Feb 3 2013 01:48:31:200AM /// 2950/16050/451/30164712/8387/Eight Mile Plains/Eight Mile Plains // Feb 3 2013 02:09:33: 017AM /// 2450/5750/ 451/30165778/8387/Springwood/Springwood // Feb 3 2013 02:44:51:363AM /// 800/2100/ 451/30166370/8387/Loganholme/Loganholme // 201年2月3日3 03:06:28:103AM 03:28:53 AM /// 0/0/451/30166916/8387/Shailer Park/// Feb 3 2013 03:28:46:553AM /// 0/13950/451/30169626/11979/Logan Central/// Feb 3 2013年7月3日上午7:18:05:6:30AM /// 0/0/451/30169632/11979/Logan Central/Logan // ///0/0/ 451/30169783/11979/Woodridge/Springwood // Feb 3 2013 07:38:32:377AM /// 1250/6400/451/30170203/11979/Logan Central/// Feb 3 2013 08:31:52:960AM /// 0/1050 /從dbo.vehicle
dbo.Vehicle:
VehicleID Number
CarNumber Text
PrimaryFleetID Number
Conditions Text
RegoNum Text
RegoExpiry Date/Time
TaxiLicNum Number
TaxiLicExpiry Date/Time
VehicleMake Text
VehicleModel Text
VehicleYear Text
OwnerID Number
OperatorID Number
示例數據
$STH = $DBH->query('SELECT * FROM dbo.Vehicle WHERE VehicleID = "451"');
echo $row->VehicleID . "/";
echo $row->CarNumber . "/";
echo $row->PrimaryFleetID . "/";
echo $row->Conditions . "/";
echo $row->OwnerID . "/";
echo $row->OperatorID . "/";
4分之451/120395399168分之5/ 1/3/
當我嘗試和運行,包括任何查詢聯接我沒有得到任何結果...
這個沒有返回值:
$ STH = $ DBH->查詢(「選擇dbo.VehicleJobHistory.BookingID, dbo.VehicleJobHistory.DriverID FROM dbo.Vehicle INNER JOIN dbo.VehicleJobHistory ON dbo.Vehicle.VehicleID = dbo.VehicleJobHistory.VehicleID WHERE TimeJobRequired> '09/03/2013'和 VehicleID = $ VehicleID「);
此返回bookingID的和DriverID的從VehicleJobHistory表數組:
$ STH = $ DBH->查詢(「選擇BookingID,DriverID FROM DBO。VehicleJobHistory WHERE TimeJobRequired>「2013年2月3日」和 VehicleID = $ VehicleID「);
我用盡幾乎所有其他組合我能想出,但只要我添加一個連接到我的查詢我不似乎得到任何工作。
如果任何人有經驗,這個問題還是可以點我在正確的方向,我將非常感激。
提前感謝!