我有一個問題要問:休眠OneToOne使用Spring和JSP
我有表用戶和USER_LOGIN加入OneToOne通過user.id - > user_login.user_id。
的問題是,當我做.updateObject(用戶)我得到2個查詢執行:
休眠:?插入到用戶(創建,修改,電子郵件,FIRST_NAME, 姓氏)值(,, (?,?,?)?Hibernate:insert into user_login values(?,?,?,?)[2012-08-15 12:15:04,192] [錯誤] [http-生物-8080-exec-1] SqlExceptionHelper [144]: 列'user_id'不能爲空
看起來l ike在2個對象之間沒有引用。如果進入實體用戶,方法setUserLogin我添加行 userLogin.setUser(this);它的工作,但我沒有誠實地找到這種方式優雅。有沒有我在實體配置 錯過了,也許這不會自動執行?
謝謝
這裏是我的實體
@Entity
@NamedQueries({ @NamedQuery(name = "user.list", query = "select u from User u") })
public class User implements java.io.Serializable {
@Column(name = "first_name", nullable = true)
private String firstName;
@OneToOne(mappedBy = "user", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@JoinColumn(name="user_id", nullable=false)
private UserLogin userLogin;
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public UserLogin getUserLogin() {
return userLogin;
}
public void setUserLogin(UserLogin userLogin) {
this.userLogin = userLogin;
//userLogin.setUser(this); THIS IS THE LINE THAT FIXES IT, BUT I DONT FIND THIS WAY ELEGANT
}
}
@Entity
@Table(name="user_login")
public class UserLogin implements java.io.Serializable {
@Column(name = "password", nullable = false)
private String password;
@OneToOne(optional = false, fetch = FetchType.LAZY)
private User user;
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
}
JSP文件:
<%@ taglib uri="http://www.springframework.org/tags/form" prefix="form"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/functions" prefix="fn"%>
<html>
<head>
<title>Registration Page</title>
</head>
<body>
<form:form action="/test" commandName="user">
<tr>
<td>User Name :</td>
<td><form:input path="firstName" /></td>
</tr>
<tr>
<td>Password :</td>
<td><form:input path="userLogin.password" /></td>
</tr>
<tr>
<td colspan="2"><input type="submit" value="Register"></td>
</tr>
</table>
</form:form>
</body>
</html>
春控制器:
@Controller(value = "/")
public class Test {
@Autowired
UserServiceImpl userServiceImpl;
@RequestMapping(method = RequestMethod.GET, value = "/test")
public void test(ModelMap model) {
model.addAttribute("user", new User());
}
@RequestMapping(method = RequestMethod.POST, value = "/test")
public void test(User user) {
userServiceImpl.update(user);
}
}
您的實體的代碼是否完整? – 2012-08-15 16:54:09
是的,我只是沒有粘貼進口。當然我也會添加更多的字段 – Dima 2012-08-16 17:09:20