0
This code works.
<!doctype html>
<body>
<form method="post" >
<?php
$conn = new mysqli('localhost', 'root', '', 'myDB');
if ($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$sql='SELECT DISTINCT counselor_name FROM counselors';
$result = $conn->query($sql);
?>
<select name="name" >
<?php
while ($row = mysqli_fetch_assoc($result)) {
echo '<option value="'.$row['counselor_name'].'">'.$row['counselor_name'] . '</option>';
}
?>
</select>
<input type="submit" value="GO!" name="go"/>
</form>
</body>
對於我的生活,我無法弄清楚如何將選擇功能併入到選項字符串來選擇一個值。 IE:如果我要設置$ filter =「John」。我想選擇「約翰」。如何添加選擇此代碼
在此先感謝
謝謝。解決方案的簡單性讓人望而生畏:-) –