我有測試程序如下圖所示:如何在gdb中查看智能指針的內部數據?
#include<memory>
#include<iostream>
using namespace std;
int main()
{
shared_ptr<int> si(new int(5));
return 0;
}
調試它:
(gdb) l
1 #include<memory>
2 #include<iostream>
3 using namespace std;
4
5 int main()
6 {
7 shared_ptr<int> si(new int(5));
8 return 0;
9 }
10
(gdb) b 8
Breakpoint 1 at 0x400bba: file testshare.cpp, line 8.
(gdb) r
Starting program: /home/x/cpp/x01/a.out
Breakpoint 1, main() at testshare.cpp:8
8 return 0;
(gdb) p si
$1 = std::shared_ptr (count 1, weak 0) 0x614c20
,只打印出的si
指針類型的信息,但如何獲取存儲在它的值(這種情況下5
)? 如何在調試過程中檢查si
的內部內容?
你是什麼意思與*「在si商店」*? int''si的值指向? –
[如何在GDB中訪問std :: tr1 :: shared \ _ptr的目標](https://stackoverflow.com/questions/24917556/how-to-access-target-of-stdtr1shared-ptr-in -gdb)| 'unique_ptr':https://stackoverflow.com/questions/22798601/how-to-debug-c11-code-with-unique-ptr-in-ddd-or-gdb –